Postgresql Postgres按日期和时区计数
我想查询一个表,找出Postgres中按日期、日期和月份创建的对象的数量 过去30天的提取计数 按天取数 按月提取计数 这对我来说很好。我遇到的问题是,我希望根据不同的时区获取数据。我已将时间存储在Postgresql Postgres按日期和时区计数,postgresql,timezone,Postgresql,Timezone,我想查询一个表,找出Postgres中按日期、日期和月份创建的对象的数量 过去30天的提取计数 按天取数 按月提取计数 这对我来说很好。我遇到的问题是,我希望根据不同的时区获取数据。我已将时间存储在UTC中。我可以在不同的时区运行这些查询 最好的方法是什么?勾选此项以获取不同时区的Postgres中的日期时间 过去30天的提取计数 按天取数 按月提取计数 也可以参考这篇博文来了解带有日期时间的时区 SELECT d.date, count(se.id) FROM (SELECT to_char(
UTC
中。我可以在不同的时区运行这些查询
最好的方法是什么?勾选此项以获取不同时区的Postgres中的日期时间
过去30天的提取计数
按天取数
按月提取计数
也可以参考这篇博文来了解带有日期时间的时区
SELECT d.date, count(se.id)
FROM (SELECT to_char(date_trunc('day', (current_date - offs)), 'YYYY-MM-DD') AS date
FROM generate_series(0, 30) AS offs) d LEFT OUTER JOIN
someTable se
ON d.date = to_char(date_trunc('day', se.created_at), 'YYYY-MM-DD')
GROUP BY d.date;
select to_char(created_at,'day') as Day,
extract(month from created_at) as Date,
count("id") as "Count"
from someTable
group by 1,2
select to_char(created_at,'Mon') as mon,
extract(year from created_at) as yyyy,
count("id") as "Count"
from someTable
group by 1,2
SELECT d.date, count(se.id)
FROM (SELECT to_char(date_trunc('day', (current_date - offs)), 'YYYY-MM-DD') AS date
FROM generate_series(0, 30) AS offs) d LEFT OUTER JOIN
someTable se
ON d.date = to_char(date_trunc('day', se.created_at::timestamp with time zone at time zone 'EST'), 'YYYY-MM-DD')
GROUP BY d.date;
select to_char(created_at::timestamp with time zone at time zone 'EST','day') as Day,
extract(month from created_at) as Date,
count("id") as "Count"
from someTable
group by 1,2
select to_char(created_at::timestamp with time zone at time zone 'EST','Mon') as mon,
extract(year from created_at) as yyyy,
count("id") as "Count"
from someTable
group by 1,2