Postgresql 如何引用外键表两次?

Postgresql 如何引用外键表两次?,postgresql,flask,sqlalchemy,flask-restless,Postgresql,Flask,Sqlalchemy,Flask Restless,我得到以下错误: u'detail':u“一个或多个映射程序未能初始化-无法继续 初始化其他映射程序。原始异常为:无法 不确定上的父/子表之间的联接条件 relationship Vote.user-存在多个外键路径链接 表。指定'foreign_keys'参数,提供 应计为包含外键的列 对父表的引用。“ 表A被定义为: class User(postgres.Model): def __init__(self, name ): self.nam

我得到以下错误:

u'detail':u“一个或多个映射程序未能初始化-无法继续 初始化其他映射程序。原始异常为:无法 不确定上的父/子表之间的联接条件 relationship Vote.user-存在多个外键路径链接 表。指定'foreign_keys'参数,提供 应计为包含外键的列 对父表的引用。“

A
被定义为:

class User(postgres.Model):

    def __init__(self,
        name
    ):
        self.name = name

    id = postgres.Column(postgres.Integer , primary_key=True , autoincrement=True)
    name = postgres.Column(postgres.String(32) , nullable=False , unique=True)
class Vote(postgres.Model):

    def __init__(self,
        user_id,
        responder_id,
        #timestamp_request,
        #timestamp_respond,
        value 
    ):
        self.user_id = user_id
        self.responder_id = responder_id
        #self.timestamp_request = timestamp_request
        #self.timestamp_respond = timestamp_respond
        self.value = value

    id = postgres.Column(postgres.Integer , primary_key=True , autoincrement=True)
    user_id = postgres.Column(postgres.Integer , postgres.ForeignKey('user.id'))
    user = postgres.relationship(User , backref=postgres.backref('votes_user'))
    responder_id = postgres.Column(postgres.Integer , postgres.ForeignKey('user.id'))
    responder = postgres.relationship(User , backref=postgres.backref('votes_responder'))
    timestamp_request = postgres.Column(postgres.DateTime , default=datetime.datetime.utcnow , nullable=False , unique=False)
    timestamp_respond = postgres.Column(postgres.DateTime , default=datetime.datetime.utcnow , onupdate=datetime.datetime.utcnow , nullable=False , unique=False)
    value = postgres.Column(postgres.Enum('up' , 'down' , name='vote_value_enum') , nullable=True)
B
的定义如下:

class User(postgres.Model):

    def __init__(self,
        name
    ):
        self.name = name

    id = postgres.Column(postgres.Integer , primary_key=True , autoincrement=True)
    name = postgres.Column(postgres.String(32) , nullable=False , unique=True)
class Vote(postgres.Model):

    def __init__(self,
        user_id,
        responder_id,
        #timestamp_request,
        #timestamp_respond,
        value 
    ):
        self.user_id = user_id
        self.responder_id = responder_id
        #self.timestamp_request = timestamp_request
        #self.timestamp_respond = timestamp_respond
        self.value = value

    id = postgres.Column(postgres.Integer , primary_key=True , autoincrement=True)
    user_id = postgres.Column(postgres.Integer , postgres.ForeignKey('user.id'))
    user = postgres.relationship(User , backref=postgres.backref('votes_user'))
    responder_id = postgres.Column(postgres.Integer , postgres.ForeignKey('user.id'))
    responder = postgres.relationship(User , backref=postgres.backref('votes_responder'))
    timestamp_request = postgres.Column(postgres.DateTime , default=datetime.datetime.utcnow , nullable=False , unique=False)
    timestamp_respond = postgres.Column(postgres.DateTime , default=datetime.datetime.utcnow , onupdate=datetime.datetime.utcnow , nullable=False , unique=False)
    value = postgres.Column(postgres.Enum('up' , 'down' , name='vote_value_enum') , nullable=True)

SQLAlchemy无法发现关系路径

user_id = Column(ForeignKey('user.id'))
user = relationship(User, backref=backref('votes_user'))
responder_id = Column(ForeignKey('user.id'))
responder = relationship(User, backref=backref('votes_responder'))
responder
关系是否必须使用
responder\u id
user\u id
加入?我知道这对我们来说是显而易见的,但是SQLAlchemy在这里不考虑列名。您可以将
responder\u id
重命名为
foobar
,这没有什么区别

定义要用于每个关系的外键

user = relationship(User, foreign_keys=[user_id], backref=backref('votes_user'))
responder = relationship(User, foreign_keys=[responder_id], backref=backref('votes_responder'))