Powerbi 动力双离合器

我正在尝试创建一个度量，它将从下表中计算值。如何计算至少有一个任务和日期的项目，以及如何计算有两个任务和日期的项目

额外问题：我如何计算至少有一个任务且没有日期（null）的项目，以及如何计算完成两个任务且没有日期的项目

---

以下4项措施适合您-

1.

one_one = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) <> BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) <> BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) <> BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 1,
    1,
    0
)

two_two = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) <> BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) <> BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) <> BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 2,
    1,
    0
)

one_no_date = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) = BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) = BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) = BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 1,
    1,
    0
)

two_no_date = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) = BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) = BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) = BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 2,
    1,
    0
)

one\u one=
var count_task_1=IF（min（project_count[task 1]）BLANK（）&&min（project_count[date 1]）BLANK（），1,0）
var count_task_2=IF（min（project_count[task 2]）BLANK（）&&min（project_count[date 2]）BLANK（），1,0）
var count_task_3=IF（min（project_count[task 3]）BLANK（）&&min（project_count[date 3]）BLANK（），1,0）
返回
如果(
（计数任务1+计数任务2+计数任务3）>=1，
1.
0
)

2.

one_one = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) <> BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) <> BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) <> BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 1,
    1,
    0
)

two_two = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) <> BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) <> BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) <> BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 2,
    1,
    0
)

one_no_date = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) = BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) = BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) = BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 1,
    1,
    0
)

two_no_date = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) = BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) = BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) = BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 2,
    1,
    0
)

two\u two=
var count_task_1=IF（min（project_count[task 1]）BLANK（）&&min（project_count[date 1]）BLANK（），1,0）
var count_task_2=IF（min（project_count[task 2]）BLANK（）&&min（project_count[date 2]）BLANK（），1,0）
var count_task_3=IF（min（project_count[task 3]）BLANK（）&&min（project_count[date 3]）BLANK（），1,0）
返回
如果(
（计数任务1+计数任务2+计数任务3）>=2，
1.
0
)

3.

one_one = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) <> BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) <> BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) <> BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 1,
    1,
    0
)

two_two = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) <> BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) <> BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) <> BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 2,
    1,
    0
)

one_no_date = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) = BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) = BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) = BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 1,
    1,
    0
)

two_no_date = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) = BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) = BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) = BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 2,
    1,
    0
)

one_no_日期=
var count_task_1=IF（min（project_count[task 1]）BLANK（）&&min（project_count[date 1]）=BLANK（），1,0）
var count_task_2=IF（min（project_count[task 2]）BLANK（）&&min（project_count[date 2]）=BLANK（），1,0）
var count_task_3=IF（min（project_count[task 3]）BLANK（）&&min（project_count[date 3]）=BLANK（），1,0）
返回
如果(
（计数任务1+计数任务2+计数任务3）>=1，
1.
0
)

4.

one_one = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) <> BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) <> BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) <> BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 1,
    1,
    0
)

two_two = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) <> BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) <> BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) <> BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 2,
    1,
    0
)

one_no_date = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) = BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) = BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) = BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 1,
    1,
    0
)

two_no_date = 

var count_task_1 = IF(min(project_count[task 1]) <> BLANK() && MIN(project_count[date 1]) = BLANK(),1,0)
var count_task_2 = IF(min(project_count[task 2]) <> BLANK() && MIN(project_count[date 2]) = BLANK(),1,0)
var count_task_3 = IF(min(project_count[task 3]) <> BLANK() && MIN(project_count[date 3]) = BLANK(),1,0)

RETURN
IF(
    (count_task_1+count_task_2+count_task_3) >= 2,
    1,
    0
)

two\u no\u日期=
var count_task_1=IF（min（project_count[task 1]）BLANK（）&&min（project_count[date 1]）=BLANK（），1,0）
var count_task_2=IF（min（project_count[task 2]）BLANK（）&&min（project_count[date 2]）=BLANK（），1,0）
var count_task_3=IF（min（project_count[task 3]）BLANK（）&&min（project_count[date 3]）=BLANK（），1,0）
返回
如果(
（计数任务1+计数任务2+计数任务3）>=2，
1.
0
)

这是输出-

您可以使用这些逻辑进行其他必要的计算

---

每行都需要标志吗？或表中的总计数。