Powershell 带有content.replace的嵌套foreach()循环未按预期设置内容(或添加内容)
我有下面的Powershell脚本,其中包含两个嵌套的foreach循环。 脚本应该从一个简单的SQL文件中获取内容,为表名添加前缀,并根据前缀/学生名写出新的SQL文件Powershell 带有content.replace的嵌套foreach()循环未按预期设置内容(或添加内容),powershell,Powershell,我有下面的Powershell脚本,其中包含两个嵌套的foreach循环。 脚本应该从一个简单的SQL文件中获取内容,为表名添加前缀,并根据前缀/学生名写出新的SQL文件 $content = Get-Content "[PATH_FILE].sql" $students = @('18adadam','18bebert','18dadavi') # $students = Get-Content "[PATH_FILE].txt" $tables = @('image','post','use
$content = Get-Content "[PATH_FILE].sql"
$students = @('18adadam','18bebert','18dadavi')
# $students = Get-Content "[PATH_FILE].txt"
$tables = @('image','post','user')
foreach ($student in $students) {
foreach ($table in $tables) {
$tablename = $student + '_' + $table
'Table name: ' + $tablename
$content = $content.Replace("TABLE ``$table``","TABLE ``$tablename``")
}
$content | Set-Content ("$student.sql")
'Content: '+ $content
}
文件按预期创建:
- 18adadam.sql
- 18bebert.sql
- 18dadavi.sql
$content = $content.Replace("TABLE ``$table``","TABLE ``$student" + "_" + "$table``")
我担心连接会在某种程度上破坏内容的编写,所以我将其更改为表名的单个变量
$tablename = $student + '_' + $table
$content = $content.Replace("TABLE ``$table``","TABLE ``$tablename``")
我添加了
'Table name: ' + $tablename
及
作为简单的调试行,以查看脚本中每个点的情况
我还试着看看如下将输出更改为单个文件是否会改变任何内容:
$content | Add-Content ("[PATH_FILE]_2.sql")
正如预期的那样,它所做的只是用正确的sql为18adam创建了一个文件,重复了三次。第二次
$content.Replace(
将找不到原始值,因为它在$content中更改了。将更改保存到其他变量
## Q:\Test\2018\10\11\SO_52758908.ps1
$content = Get-Content ".\template.sql"
$students = @('18adadam','18bebert','18dadavi')
# $students = Get-Content "[PATH_FILE].txt"
$tables = @('image','post','user')
foreach ($student in $students) {
$Newcontent = $content
foreach ($table in $tables) {
$tablename = "{0}_{1}" -f $student,$table
'Table name: ' + $tablename
$Newcontent = $Newcontent.Replace("TABLE ``$table``","TABLE ``$tablename``")
}
$Newcontent | Set-Content ("$student.sql")
'Content: '
$Newcontent
}
Doh!谢谢你!我以为这是类似的事情。但我无法准确地指出我到底出了什么问题。
$content | Add-Content ("[PATH_FILE]_2.sql")
## Q:\Test\2018\10\11\SO_52758908.ps1
$content = Get-Content ".\template.sql"
$students = @('18adadam','18bebert','18dadavi')
# $students = Get-Content "[PATH_FILE].txt"
$tables = @('image','post','user')
foreach ($student in $students) {
$Newcontent = $content
foreach ($table in $tables) {
$tablename = "{0}_{1}" -f $student,$table
'Table name: ' + $tablename
$Newcontent = $Newcontent.Replace("TABLE ``$table``","TABLE ``$tablename``")
}
$Newcontent | Set-Content ("$student.sql")
'Content: '
$Newcontent
}