Python 2.7 得到一个；索引器：列表索引超出范围“；这对我来说没有意义

我有一个任务要做，就是把盖茨比的故事拿走，去掉所有的标点符号，用“0”s替换“o”。根据故事中的文字，我必须破解一个格式为w1w2w3的PDF，并通过循环不断上升（w2w3w4、w3w4w5、w4w5w6等），直到找到密码。我的问题是我得到了一个索引器：列表索引超出了下一行的范围

password = word_list[list_1] + word_list[list_2] + word_list[list_3]

如果能帮我找到错误的原因，我将不胜感激，因为我在过去的两天里一直在看它，但都没有用。如果您注意到我的代码中还有其他错误，请指出它们

import re
import PyPDF2

# Defining the function called "pdf_cracker"
def pdf_cracker():
    # Import the shuffle
`   from random import shuffle
    # Open Gadsby story and define it as the variable "string"
    string = open("gadsby.txt", "r").read()
    # Uses substitution in the RE module to only include characters from a-z, A-Z and 0-9
    new_str = re.sub("[^a-zA-Z0-9]", " ",string)
    open("gadsby_no_punctuation.txt", "w").write(new_str)
    gadsby_no_punctuation = open("gadsby_no_punctuation.txt", "r").read().split()

    word_list = [gadsby_no_punctuation]

    list_1 = 0
    list_2 = 1
    list_3 = 2


for item in word_list:          
    password = word_list[list_1] + word_list[list_2] + word_list[list_3] # ERROR ON THIS LINE
    password = password.replace("o", "0")
    password = password.replace("O", "0")
    print password

    from PyPDF2 import PdfFileReader, PdfFileWriter
    pdf_file = ("crack_me.pdf", "rb")

    if pdf.isEncrypted == False:
        print "The file you're trying to crack doesn't have a password"

    if(pdf_file.decrypt(password) == 1):
        print "O " + password + " is the password!"
        break

    else:       
        print "X " + password + " is not the password"
        list_1 = list_1 + 1
        list_2 = list_2 + 1
        list_3 = list_3 + 1

if __name__ == "__main__":
    zip_cracker() # Ignore this line - this is another part of the program, not throwing up any errors.
    pdf_cracker()

---

您正在创建gadsby列表，然后将其放入另一个列表中

gadsby_no_punctuation = "a b c d e f g".split() # A test string
>>> gadsby_no_punctuation
['a', 'b', 'c', 'd', 'e', 'f', 'g']
>>> word_list = [gadsby_no_punctuation]
>>> word_list
[['a', 'b', 'c', 'd', 'e', 'f', 'g']] # a list inside a list
>>> len(word_list)
1 # only 1 item in the list

而不是

word_list = [gadsby_no_punctuation]

使用[：]复制gadsby列表

word_list = gadsby_no_punctuation[:]

---

只要至少有3个单词，您就不会再出现该错误

每次分配5个单词。检查：我想这就是发生的事情吗？在哪里？看看链接是否有用