Python 2.7 python/API中的if…elif语句

我正在编写一个脚本，对人们的名字进行排序。我使用csv模块进行了这项工作，但由于这将与一个更大的熊猫项目相关联，我想我会转换它

我需要将单个名称字段拆分为第一个、中间个和最后一个字段。原始字段首先具有第一个名称。理查德·韦恩·范·戴克

我把名字分开了，但想让“Van Dyke”成为我的姓

以下是我的csv模块代码：

with open('inputfil.csv') as inf:
    docs = csv.reader(inf)
    next(ccaddocs, None)
    for i in docs:
        #print i
        fullname = i[1]#it's the second column in the input file
        namelist =fullname.split(' ') 
        firstname = namelist[0]
        middlename = namelist[1]
        if len(namelist) == 2:
            lastname = namelist[1]
            middlename = ''
        elif len(namelist) == 3:
            lastname = namelist[2]
        elif len(namelist) == 4:
            lastname = namelist[2] + " " + namelist[3] #gets Van Dyke in lastname
        print "First: " + firstname + " middle: " + middlename + " last: " + lastname

以下是我正在努力解决的基于pandas的代码：

    df = pd.DataFrame({'Name':['Richard Wayne Van Dyke','Gary Del Barco','Dave Allen Smith']})
df = df.fillna('')
df =df.astype(unicode)
splits = df['Name'].str.split(' ', expand=True)

df['firstName'] = splits[0]
if  splits[2].notnull and splits[3].isnull:#this works for Bret Allen Cardwell

    df['lastName'] = splits[2]
    df['middleName'] = splits[1]
    print "Case 1: First: " + df['firstName'] + " middle: " +df['middleName'] + " last: " + df['lastName']
elif splits[2].all() == 'Del':#trying to get last name of "Del Barco"
    print 'del'
    df['middleName'] = ''
    df['lastName'] = splits[2] + " " + splits[3]
    print "Case 2: First: " + df['firstName'] + " middle: " +df['middleName'] + " last: " + df['lastName']

elif splits[3].notnull: #trying to get last name of "Van Dyke"
    df['middleName'] = splits[1]
    df['lastName'] = splits[2] + " " + splits[3]
    print "Case 3: First: " + df['firstName'] + " middle: " +df['middleName'] + " last: " + df['lastName']

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我缺少一些基本的东西

谢谢你的回复。我明白你的逻辑，但当我打印“lastnames”时，我得到：>>>01 2 3 2 Dave Allen Smith无>>>我不确定这里发生了什么。我希望看到一份姓氏列表。当我将lastnames更改为

splits[2]+splits[3]

时，我得到：>>>0 VanDyke 1 NaN 2 NaN数据类型：对象>>>您是否尝试过打印拆分以查看实际存在的内容？是：0 Richard 1 Gary 2 Dave姓名：0，数据类型：对象0 Wayne 1 Del 2 Allen姓名：1，数据类型：对象0 Van 1 Barco 2 Smith姓名：2，数据类型：对象0 Dyke 1 None 2 None姓名：3，数据类型：objectI尚未找到熊猫，但已修改了我的csv代码，该代码将在将数据传递给熊猫之前完成工作。我没有像上面的csv代码那样使用

csv.reader

，而是将其更改为

csv.DictReader

。通过将数据传递到字典，可以很容易地使用Name字段的键值对来获得csv代码。

if len(name) >= 3: # (assume that user only has one middle name)

  firstname = splits[0]
  middlename = splits[1]
  lastnames = splits[2:] ( catch all last names into a list )