Python 3.x 刮取标记值

Python 3.x 刮取标记值,python-3.x,web-scraping,beautifulsoup,Python 3.x,Web Scraping,Beautifulsoup,我想问我是否可以使用beautifulsoup刮取标签的值: 我想要一个img src: <img class="product-pic" src="//cdn.shopify.com/s/files/1/1385/4109/products/Beef_Patties_grande_41a52a6f-1d85-499c-be1d-06ecb318c2ad_large.jpg?v=1469212539" alt="Beef Burgers"> 我正在做的是: containers[0

我想问我是否可以使用beautifulsoup刮取标签的值: 我想要一个img src:

<img class="product-pic" src="//cdn.shopify.com/s/files/1/1385/4109/products/Beef_Patties_grande_41a52a6f-1d85-499c-be1d-06ecb318c2ad_large.jpg?v=1469212539" alt="Beef Burgers">
我正在做的是:

containers[0].find("img").next_element.next_element.next_element.next_element.next_element.next_element
但我没有得到预期的输出,我得到的是:

<a href="/collections/beef/products/beef-burgers">Beef Burgers</a>


任何帮助都将不胜感激,谢谢

我得到了问题的答案,我所要做的只是简单:

img = containers[0].find("img",{"class":"product-pic"})
src = img["src"]
输出:

'//cdn.shopify.com/s/files/1/1385/4109/products/Beef_Patties_grande_41a52a6f-1d85-499c-be1d-06ecb318c2ad_large.jpg?v=1469212539'

如果你喜欢汤,你会得到什么?选择一个(“img[class='product-pic']”['src']?@SIM谢谢你的回复,我得到了我的答案,我已经在下面发布了
'//cdn.shopify.com/s/files/1/1385/4109/products/Beef_Patties_grande_41a52a6f-1d85-499c-be1d-06ecb318c2ad_large.jpg?v=1469212539'