Python 3.x 如何使用Python脚本为Excel工作表中的值形成一对多关系？

我有一份Excel，其中包含以下几张表格，见附件：

现在，我想在两张纸之间生成一对多算法，这意味着对于SOURCE_KEY的每个值，都要打印RECEIVER SHEET中的所有值

指：

INFORMATION SOURCE KEY 1: parent
    SERVICE PROVIDER  KEY 1: child
    SERVICE PROVIDER KEY  2: child 
INFORMATION SOURCE KEY 2: parent 
    SERVICE PROVIDER  KEY 3: child
    SERVICE PROVIDER KEY  4: child  

下面是编写的代码：

def loop_2100A(self,source_keys):   
    Information_Reciever = pd.read_excel(filename, sheet_name=1, index_col=0)
    Reciever_keys=list(Information_Reciever["RECIEVER KEY"])
    Source_key_in_Reciever=list(Information_Reciever.index.values)
    elem =1
    elems_in_both_lists = set(Source_key_in_Reciever) & set(Reciever_keys

    if elem in elems_in_both_lists:
        print("Value of Source key inside if ", elem)
        print("Value of Reciever Key inside if", elem)
        res = dict(zip(Source_key_in_Reciever, Reciever_keys))

    for p in source_keys:
            print("Value of P is ",p)
       for x,y in res.items():
                print("COMPARING of p is {} and Value of x is {} IF EQUAL GO AHEAD ".format(p,x))
          if[p==x]:
                print("Value of Source key passed in 2100A is", x)
                print("Value of Reciever key passed to 2100B is", y)
               # CALLING SOME FUNCTION TO PERFORM OPERATION ONLY WHEN P==X
        else:
            print("Return back to Parent tag")
    return len(source_keys)

def run(self):
Read_Excel = pd.read_excel(filename, sheet_name=0,index_col=0)
    source_keys = list(Read_Excel.index.values)
    segs = self.loop_2100A(Parser, filename,source_keys)

输出：

*********Inside 2100A loop*********
Value of Source key inside if  1
Value of Reciever Key inside if 1
Dictionary formed is {1: 2, 2: 3}
Value of P is  1
COMPARING of p is 1 and Value of x is 1 IF EQUAL GO AHEAD
Value of Parent Source key passed in 2100A is 1
Value of Child Reciever key passed to 2100B is 2
COMPARING of p is 1 and Value of x is 2 IF EQUAL GO AHEAD
****Value of Parent Source key passed in 2100A is 2
Value of Child Reciever key passed to 2100B is 3****
Value of P is  2
COMPARING of p is 2 and Value of x is 1 IF EQUAL GO AHEAD
**Value of Parent Source key passed in 2100A is 1
Value of Child Reciever key passed to 2100B is 2**
COMPARING of p is 2 and Value of x is 2 IF EQUAL GO AHEAD
Value of Parent Source key passed in 2100A is 2
Value of Child Reciever key passed to 2100B is 3

Process finished with exit code 0

预期产出：

*********Inside 2100A loop*********
Value of Source key inside if  1
Value of Reciever Key inside if 1
Dictionary formed is {1: 2, 2: 3}
Value of P is  1
COMPARING of p is 1 and Value of x is 1 IF EQUAL GO AHEAD
Value of Parent Source key passed in 2100A is 1
Value of Child Reciever key passed to 2100B is 2
COMPARING of p is 1 and Value of x is 2 IF EQUAL GO AHEAD
NOT EQUAL Return back to Parent tag
Value of P is  2
COMPARING of p is 2 and Value of x is 1 IF EQUAL GO AHEAD
NOT EQUAL Return back to Parent tag
COMPARING of p is 2 and Value of x is 2 IF EQUAL GO AHEAD
Value of Parent Source key passed in 2100A is 2
Value of Child Reciever key passed to 2100B is 3

Process finished with exit code 0

输出中大胆的错误。因此，即使P和X的比较失败，它也会进入if条件，或者my be for循环和if条件错误。

使用if P==X:而不是if[P==X]：。他们是不同的

如果[2==3]：如果[False]： 打印“通过”将打印“通过” 如果2==3：如果为假： 打印“通过”“已通过”将不会被打印 [False]对象被视为True。您可以通过执行printbool[False]来检查它，它将打印True

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您可以查看关于Python的文档。

您能帮我回答这个问题吗：@HarshitKakkar我发布了一个问题的答案：

*********Inside 2100A loop*********
Value of Source key inside if  1
Value of Reciever Key inside if 1
Dictionary formed is {1: 2, 2: 3}
Value of P is  1
COMPARING of p is 1 and Value of x is 1 IF EQUAL GO AHEAD
Value of Parent Source key passed in 2100A is 1
Value of Child Reciever key passed to 2100B is 2
COMPARING of p is 1 and Value of x is 2 IF EQUAL GO AHEAD
NOT EQUAL Return back to Parent tag
Value of P is  2
COMPARING of p is 2 and Value of x is 1 IF EQUAL GO AHEAD
NOT EQUAL Return back to Parent tag
COMPARING of p is 2 and Value of x is 2 IF EQUAL GO AHEAD
Value of Parent Source key passed in 2100A is 2
Value of Child Reciever key passed to 2100B is 3

Process finished with exit code 0