Python 3.x 在python中为重复列表值添加唯一值
我有一个包含重复值的列表。我想通过添加字符“v1”或v2来保留重复的值。。等等。如果特定数字重复相同次数,计数器将增加Python 3.x 在python中为重复列表值添加唯一值,python-3.x,list,data-structures,Python 3.x,List,Data Structures,我有一个包含重复值的列表。我想通过添加字符“v1”或v2来保留重复的值。。等等。如果特定数字重复相同次数,计数器将增加 mk=['1','1','2','3','2','4','4','4','5'] 输出将如下所示 ['1','1_v1','2','2_v1','3','4','4_v1','4_v2','5'] 创建字典以保持元素的出现频率,然后使用字典向元素追加值 mk = ['1','1','2','3','2','4','4','4','5'] my_dict = {key:0 fo
mk=['1','1','2','3','2','4','4','4','5']
输出将如下所示
['1','1_v1','2','2_v1','3','4','4_v1','4_v2','5']
创建字典以保持元素的出现频率,然后使用字典向元素追加值
mk = ['1','1','2','3','2','4','4','4','5']
my_dict = {key:0 for key in mk}
for i in range(len(mk)):
my_dict[mk[i]] += 1 #increase the occurrence count
if my_dict[mk[i]] > 1: #check if the element occurred more than once
mk[i] = mk[i]+"_v"+str(my_dict[mk[i]] - 1) #if yes append the value