Python 3.x 随机不返回预期结果

#Python 3.7.2

所以我是新手，只想让我的程序在随机数匹配时运行“True”，如果随机数不匹配时运行“False”，这对每个人来说都是非常基本的，但我很慢

def firstSet():
  import random
  for x in range(1):
    return(random.randint(1,10))

def secondSet():import random
  for x in range(1):
    return(random.randint(1,10))

def view():
  return(secondSet(), firstSet())

def theMatch():
  if secondSet() == firstSet():
    return(True, view())
  else:
    return(False, view())

print(theMatch()) 


theMatch()

---

我希望输出类似于

（True，（5,5））

或

（False，（2,3））

，但实际输出通常类似于

（True，（10,2））

或

（False，（7,7））

完全随机。我知道有很多不同的方法可以用更简单的方法编写这个程序，但我只是想知道我哪里出错了。谢谢

欢迎来到堆栈溢出

代码无法正常运行的原因是，您实际上多次重新计算该“随机”值，包括在检查它们是否匹配之后，以及在打印之前重新计算该值

让我们稍微浏览一下您的代码：
调用match（）时，会发生以下情况：

如果secondset（）==firstset（）：这里，您正在计算随机数 值，如果它们匹配，则返回true，并返回另一组 随机变量（因为您正在调用view（），而view（）调用 第二套和第一套）

如果没有，则返回“False”，然后再次调用view，它将再次重新计算随机整数

实现您所需的示例程序（带注释）如下：

# Grab the random library
import random

# Create a function to calculate a random number
def create_random_number():
    # No need for a loop, just use x to denote a random number between 1 and 10
    x = random.randint(1,10)
    # Return that random number
    return x

# This is your main function.
# This is sometimes called a "driver" program
def main():
    # Store a random value in the first_val variable
    first_val = create_random_number()
    # Store a random value in the second_val variable
    second_val = create_random_number()

    # If they added up, print out what they were, and that it was a true match
    if first_val == second_val:
        print(first_val, " and ", second_val, " match, this is TRUE")
    # If not, print out what they were, and that it was not a match
    else:
        print(first_val, " and ", second_val, " do not match, this is FALSE")

# Actually execute your main function
main()

希望这有助于回答您的问题。简而言之，这是因为您正在比较两个值，然后获取不同的随机值以打印出来（这有助于按顺序遍历这些函数的逻辑以及正在发生的事情）

下面是您的代码注释，解释发生了什么：

def firstSet():
  import random
  for x in range(1):
    return(random.randint(1,10))

def secondSet():import random
  for x in range(1):
    return(random.randint(1,10))

def view():
  return(secondSet(), firstSet())

def theMatch():
    # This pair here are the first and second random integers
  if secondSet() == firstSet():
    # Now, view() gets called which returns the functions, therefore returning a DIFFERENT set of random integers than the ones being tested
    return(True, view())
  else:
    # Now, view() gets called which returns the functions, therefore returning a DIFFERENT set of random integers than the ones being tested
    return(False, view())

print(theMatch()) 


theMatch()

下面是对您的代码的一个修复，它似乎对我有效：

def firstSet():
    import random
    for x in range(1):
        return(random.randint(1,10))

def secondSet():
    import random
    for x in range(1):
        return(random.randint(1,10))

def theMatch():
    firstVal = firstSet()
    secondVal = secondSet()

    if secondVal == firstVal:
    # Now, view() gets called which returns the functions, therefore returning a DIFFERENT set of random integers than the ones being tested
        return(True, secondVal, firstVal)
    else:
    # Now, view() gets called which returns the functions, therefore returning a DIFFERENT set of random integers than the ones being tested
        return(False, secondVal, firstVal)

print(theMatch()) 


theMatch()

---

您的代码正在多次重新计算随机值。。。。