Python 3.x 如何使用python查找和更新XML文件内容

比如说

 <managedObject class="New" distName="MB-85404/TB-85404/ST-4/a" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="b">enabled</p>
          <p name="c">640ms</p>
          <p name="d">320ms</p>
          <p name="e">640ms</p>
          <p name="f">1280ms</p>
          <p name="g">6</p>
    </managedObject>
<managedObject class="new" distName="AL-76867/MB-85404/TB-85404/ST-4/b" version="xL20A_1911_002" operation="open">
          <p name="h">320ms</p>
          <p name="i">enabled</p>
          <p name="j">640ms</p>
          <p name="k">320ms</p>
          <p name="l">640ms</p>
          <p name="a">1280ms</p>
          <p name="l">6</p>
    </managedObject>
<managedObject class="New" distName="MB-85404/TB-85404/ST-4/c" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="p">enabled</p>
          <p name="q">640ms</p>
          <p name="r">320ms</p>
          <p name="s">640ms</p>
          <p name="t">1280ms</p>
          <p name="u">6</p>
    </managedObject>

编辑2

通过这段代码，我试图找到与

regex loc

匹配的

distname

，在

managedObject

内部，我试图找到tag

，我想将

“4444 New York”

更新为

“3444 South texas”

，这给了我下面提到的错误

locat.string="3444 South texas"
AttributeError: 'NoneType' object has no attribute 'string'

---

我希望我正确理解了你的问题，这将找到所有

distName=“MB-85404/TB-85404/ST-4/[a或b或c]

标记，并替换

85409

的

85404

和更新

标记：

import re
from bs4 import BeautifulSoup


xml_data = ''' <managedObject class="New" distName="MB-85404/TB-85404/ST-4/a" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="b">enabled</p>
          <p name="c">640ms</p>
          <p name="d">320ms</p>
          <p name="e">640ms</p>
          <p name="f">1280ms</p>
          <p name="g">6</p>
    </managedObject>
<managedObject class="new" distName="AL-76867/MB-85404/TB-85404/ST-4/b" version="xL20A_1911_002" operation="open">
          <p name="h">320ms</p>
          <p name="i">enabled</p>
          <p name="j">640ms</p>
          <p name="k">320ms</p>
          <p name="l">640ms</p>
          <p name="a">1280ms</p>
          <p name="l">6</p>
    </managedObject>
<managedObject class="New" distName="MB-85404/TB-85404/ST-4/c" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="p">enabled</p>
          <p name="q">640ms</p>
          <p name="r">320ms</p>
          <p name="s">640ms</p>
          <p name="t">1280ms</p>
          <p name="u">6</p>
    </managedObject>'''

soup = BeautifulSoup('<data>' + xml_data + '</data>', 'xml')

r = re.compile(r'^MB-85404/TB-85404/ST-4/(?:a|b|c)')

for o in soup.find_all('managedObject', distName=r):
    o['distName'] = o['distName'].replace('85404', '85409')
    p = o.find('p', {'name':'a'})
    p.string = 'UPDATED ' + p.string

soup.data.unwrap()
print(soup)

---

EDIT2:要替换整个文件，请执行以下操作：

with open("C:/files/abcd.xml", "r") as f_in:
    xml_data = f_in.read()

with open("C:/files/output.xml", "w") as f_out:
    f_out.write(xml_data.replace("85409","85904"))

---

谢谢Andrej，我会尝试一下，我只是有点怀疑，当您更新p标记时，它是否会在到来时更新整个XML文件，或者当managedObject匹配bmmanagedObject class=“New”distName=“MB-85409/TB-85409/ST-4/[a或b或c]”时更新

中使用
distName=“MB-85404/TB-85404/ST-4/[a或b或c]
更新
，并且如果我想在整个XML文件上更新“85404”到“85409”，无论其位置如何，我该怎么做。？对不起，我问的问题太多了，我是新手。这没关系，我们可以在distName中更改它，但我想知道我们是否可以在整个工作表中更改它，就像在记事本中一样查找并替换所有类型的内容？@AkashRathor然后您可以使用
str.replace
，例如，将XML读取到变量
XML\u data
，然后执行
xml\u data=xml\u数据。替换（'85404'，'85409'）
并将
xml\u数据保存到新文件中。
import re
from bs4 import BeautifulSoup


xml_data = ''' <managedObject class="New" distName="MB-85404/TB-85404/ST-4/a" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="b">enabled</p>
          <p name="c">640ms</p>
          <p name="d">320ms</p>
          <p name="e">640ms</p>
          <p name="f">1280ms</p>
          <p name="g">6</p>
    </managedObject>
<managedObject class="new" distName="AL-76867/MB-85404/TB-85404/ST-4/b" version="xL20A_1911_002" operation="open">
          <p name="h">320ms</p>
          <p name="i">enabled</p>
          <p name="j">640ms</p>
          <p name="k">320ms</p>
          <p name="l">640ms</p>
          <p name="a">1280ms</p>
          <p name="l">6</p>
    </managedObject>
<managedObject class="New" distName="MB-85404/TB-85404/ST-4/c" version="xL20A_1911_002" operation="open">
          <p name="a">320ms</p>
          <p name="p">enabled</p>
          <p name="q">640ms</p>
          <p name="r">320ms</p>
          <p name="s">640ms</p>
          <p name="t">1280ms</p>
          <p name="u">6</p>
    </managedObject>'''

soup = BeautifulSoup('<data>' + xml_data + '</data>', 'xml')

r = re.compile(r'^MB-85404/TB-85404/ST-4/(?:a|b|c)')

for o in soup.find_all('managedObject', distName=r):
    o['distName'] = o['distName'].replace('85404', '85409')
    p = o.find('p', {'name':'a'})
    p.string = 'UPDATED ' + p.string

soup.data.unwrap()
print(soup)

<?xml version="1.0" encoding="utf-8"?>
 <managedObject class="New" distName="MB-85409/TB-85409/ST-4/a" operation="open" version="xL20A_1911_002">
<p name="a">UPDATED 320ms</p>
<p name="b">enabled</p>
<p name="c">640ms</p>
<p name="d">320ms</p>
<p name="e">640ms</p>
<p name="f">1280ms</p>
<p name="g">6</p>
</managedObject>
<managedObject class="new" distName="AL-76867/MB-85404/TB-85404/ST-4/b" operation="open" version="xL20A_1911_002">
<p name="h">320ms</p>
<p name="i">enabled</p>
<p name="j">640ms</p>
<p name="k">320ms</p>
<p name="l">640ms</p>
<p name="a">1280ms</p>
<p name="l">6</p>
</managedObject>
<managedObject class="New" distName="MB-85409/TB-85409/ST-4/c" operation="open" version="xL20A_1911_002">
<p name="a">UPDATED 320ms</p>
<p name="p">enabled</p>
<p name="q">640ms</p>
<p name="r">320ms</p>
<p name="s">640ms</p>
<p name="t">1280ms</p>
<p name="u">6</p>
</managedObject>

for o in soup.find_all('managedObject', {'distName': True}):
    o['distName'] = o['distName'].replace('85404', '85409')

with open("C:/files/abcd.xml", "r") as f_in:
    xml_data = f_in.read()

with open("C:/files/output.xml", "w") as f_out:
    f_out.write(xml_data.replace("85409","85904"))