Python 3.x loopinbg问题-尝试从列表中查找素数

我得到一个数字列表，使用python，我需要在列表中找到素数并打印出来

我试过几种不同的方法，但都不能完全奏效。我的最新尝试如下，但它只是返回所有数字，并显示消息，说明它是一个素数，但最后一个除外

    odd_numbers = [1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29] 
    x = 0
    y = len(odd_numbers) - 1  

    # If given number is greater than 1 
    #if odd_numbers[x] > 2: 

    # Iterate from 2 to n / 2  
    for i in range(0, y):  
        # If num is divisible by any number between  
        # 2 and n / 2, it is not prime  
        if (odd_numbers[x] % 2) == 0: 
            break

        else: 
            pr_no =  odd_numbers[x]
            print(odd_numbers[x], "is a prime number") 
            x = x + 1

    else: 
       print(odd_numbers[x], "is not a prime number")

它应该做的是打印出：

2是质数

---

3是列表中所有素数的素数等

我的回答对你有帮助吗？

odd_numbers = [1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29]

for x in odd_numbers:
    if x > 1:
        for y in range(2,x):
            if (x % y) == 0:
#               print(x,"is not a prime number")
#               print(y,"times",x//y,"is",x)
               break
        else:
            print(y,"is a prime number")
#    else:
#        print(x, "is not a prime number")