Python urwid watch_文件块按键

我有以下urwid程序，显示按下的键，或从Popen'd程序输入的任何行：

#!/usr/bin/env python
import urwid
from threading import Thread
from subprocess import Popen, PIPE
import time
import os


class MyText(urwid.Text):
    def __init__(self):
        super(MyText, self).__init__('Press Q to quit', align='center')

    def selectable(self):
        return True

    def keypress(self, size, key):
        if key in ['q', 'Q']:
            raise urwid.ExitMainLoop()
        else:
            self.set_text(repr(key))


class Writer(object):
    def __init__(self):
        self._child = Popen(
                'for i in `seq 5`; do sleep 1; echo $i; done',
                #"ssh localhost 'for i in `seq 5`; do sleep 1; echo $i; done'",
                shell=True, stdout=PIPE, stderr=PIPE)

    def file(self):
        return self._child.stdout

    def fileno(self):
        return self._child.stdout.fileno()

w = Writer()
txt = MyText()
top = urwid.Filler(txt)
mainloop = urwid.MainLoop(top)

def on_writer():
    c = w.file().read(1)
    if c == '': # terminated
        mainloop.remove_watch_file(w.fileno())
        return
    if c == '\n':
        return
    txt.set_text(c)
    mainloop.draw_screen()

mainloop.watch_file(w.fileno(), on_writer)

mainloop.run()

上面的程序可以运行，但是如果我将Popen'd命令更改为

ssh localhost…

版本，程序将停止显示按键，直到

ssh localhost…

命令完成。为什么呢

---

环境：CentOS 6.6、Python 2.7.4、urwid 1.3.1-dev.

问题是ssh试图操作其

stdin

。将其

stdin

设置为虚拟文件描述符可以修复它

class Writer(object):
    def __init__(self):
        r, w = os.pipe()
        self._child = Popen(
                #'for i in `seq 5`; do sleep 1; echo $i; done',
                "ssh localhost 'for i in `seq 5`; do sleep 1; echo $i; done'",
                shell=True, stdin=r, stdout=PIPE, stderr=PIPE)
        os.close(w)