在python中，如何从具有给定起始和结束模式的字符串中删除某些行？

在下面的字符串中，我必须删除以日期开头、以工作注释结尾的行

input_String= "22/01/2020 - aman singh (Work notes)
Two roads diverged in a yellow wood,
And sorry I could not travel both
And be one traveler, long I stood

21/01/2020 - tom cruise (Work notes)
And looked down one as far as I could
To where it bent in the undergrowth.

23/01/2020 - tom cruse (Work notes)
Then took the other, as just as fair
And having perhaps the better claim."

输出字符串=

Two roads diverged in a yellow wood,
And sorry I could not travel both
And be one traveler, long I stood

And looked down one as far as I could
To where it bent in the undergrowth.

Then took the other, as just as fair
And having perhaps the better claim.

您可以使用替换线

import re 

pat = re.compile(r'^\d{2}/\d{2}\/\d{4}.+\(Work notes\)\n', flags=re.M)
# Match from date pattern at start of line to (Work notes) at the end

print(pat.sub('', input_String))  # replace that line with empty string

---

你试过什么？什么不起作用？你得到了什么？你期待什么？什么对你的代码不起作用？它在哪里？这是一个相当简单的问题，但我想知道你尝试了什么，在你提供答案之前绊倒在哪里。请考虑解释一下你的代码背后的内容。@卡莱斯蒂尼准备好了。

import re

input_String= '''22/01/2020 - aman singh (Work notes)
Two roads diverged in a yellow wood,
And sorry I could not travel both
And be one traveler, long I stood

21/01/2020 - tom cruise (Work notes)
And looked down one as far as I could
To where it bent in the undergrowth.

23/01/2020 - tom cruse (Work notes)
Then took the other, as just as fair
And having perhaps the better claim.'''


temp = re.compile(r'\d{2}/\d{2}/\d{4} - [a-zA-Z ]+ \(Work notes\)\n') # saving template of regex
string = temp.sub('', input_String)  # replacing regex template in string to ''
print(string)