Python 在matplotlib中为图例线着色

我想在图例中围绕线条进行着色，如下图所示

我尝试将“hatch”与以下内容结合使用：

handles, labels = ax0.get_legend_handles_labels()

handles[0] = mpatches.Patch(facecolor='red', edgecolor='red', alpha=1.0, linewidth=0, label="Theory (MLL)", hatch='-')

handles[i].set_facecolor('pink')

first_legend = ax0.legend(handles, labels, loc=0, frameon=0, borderpad=0.1)

ax = ax0.add_artist(first_legend)

但这会导致矩形有多条线，如下所示：

handles, labels = ax0.get_legend_handles_labels()

handles[0] = mpatches.Patch(facecolor='red', edgecolor='red', alpha=1.0, linewidth=0, label="Theory (MLL)", hatch='-')

handles[i].set_facecolor('pink')

first_legend = ax0.legend(handles, labels, loc=0, frameon=0, borderpad=0.1)

ax = ax0.add_artist(first_legend)

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通过将两个句柄放在一个元组中，可以将它们绘制在另一个句柄之上（请参阅本指南中关于HandlerTuple的部分：）。除此之外，要使线延伸到面片的边缘，您可以使用自定义版本的正常线处理程序，其

marker\u pad=0

from matplotlib import pyplot as plt 
import matplotlib.patches as mpatches
from matplotlib.legend_handler import HandlerLine2D
import numpy as np

line, = plt.plot(range(10), color = 'red')
patch = mpatches.Patch(facecolor='pink', alpha=1.0, linewidth=0)
plt.legend([(patch, line)], ["Theory"], handler_map = {line : HandlerLine2D(marker_pad = 0)} )
plt.show()