有没有办法在Python中不打印任何回溯错误消息

我有一些这样的代码

    import paramiko
        try:
            client = paramiko.SSHClient()
            client.set_missing_host_key_policy(paramiko.AutoAddPolicy())
            client.connect(IP, username=myusername,password=mypassword,timeout=3) 
        except:
            print ("[-] Wrong : "+ip+" : "+username+" : "+password)

当我运行它时，它会不断地回溯SSH问题，例如：

Traceback (most recent call last):
paramiko.ssh_exception.SSHException: Error reading SSH protocol banner

我想知道是否可以不在屏幕上打印任何回溯消息？ 谢谢

以下是全部错误：

Traceback (most recent call last):
  File "test123.py", line 50, in function1
    client.connect(ip, username=myusername, password=mypassword,timeout=3)
  File "/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages/paramiko/client.py", line 380, in connect
    look_for_keys, gss_auth, gss_kex, gss_deleg_creds, gss_host)
  File "/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages/paramiko/client.py", line 621, in _auth
    raise saved_exception
  File "/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages/paramiko/client.py", line 608, in _auth
    self._transport.auth_password(username, password)
  File "/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages/paramiko/transport.py", line 1271, in auth_password
    return self.auth_handler.wait_for_response(my_event)
  File "/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages/paramiko/auth_handler.py", line 208, in wait_for_response
    raise e
paramiko.ssh_exception.AuthenticationException: Authentication failed.

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/work.py", line 920, in _bootstrap_inner
    self.run()
  File "/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/work.py", line 868, in run
    self._target(*self._args, **self._kwargs)
  File "test123.py", line 56, in slaveWork
    except paramiko.ssh_exception:
TypeError: catching classes that do not inherit from BaseException is not allowed

Exception: Error reading SSH protocol banner
Traceback (most recent call last):
  File "/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages/paramiko/transport.py", line 1888, in _check_banner
    buf = self.packetizer.readline(timeout)
  File "/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages/paramiko/packet.py", line 331, in readline
    buf += self._read_timeout(timeout)
  File "/Library/Frameworks/Python.framework/Versions/3.4/lib/python3.4/site-packages/paramiko/packet.py", line 498, in _read_timeout
    raise EOFError()
EOFError

---

你可以完成你的尝试，只是做一个一般的捕获，然后什么也不做

import paramiko
try:
    client = paramiko.SSHClient()
    client.set_missing_host_key_policy(paramiko.AutoAddPolicy())
    client.connect(IP, username=myusername,password=mypassword,timeout=3)
except Exception as e:
    pass

---

最好的选择可能是使用该模块。
对于Python 2.x，您可以执行以下操作：

import sys
import paramiko

sys.tracebacklimit = 0

try:
    client = paramiko.SSHClient()
    client.set_missing_host_key_policy(paramiko.AutoAddPolicy())
    client.connect(IP, username=myusername,password=mypassword,timeout=3) 
except:
    print ("[-] Wrong : "+ip+" : "+username+" : "+password) 

对于Python3.5（），有些人报告说应该将其设置为

None

才能工作，即：

sys.tracebacklimit = None

---

对于引发的多个异常，报告的某些人员不保证工作（）.

您的

try

没有

expect

。如果除了paramiko.ssh\u异常之外您还有

。SSHException:

而不是您现在拥有的。您是否在您提供的链接中尝试了

sys.tracebacklimit=0

或

sys.tracebacklimit=None

“当设置为0或更小时，所有回溯信息将被抑制，并且只打印异常类型和值。”。在这种情况下，我仍然会收到一个错误，但我只会收到一份简历。