Python 从字符串输出中剥离制表符、换行符和空格，但保留一个空格，以便不连接单词

我有一个列表3，有一个元素，一个字符串：

[['\n\n\n Headquarters or Regional Office\n\n\n\n\n\t\t\t\t\t\t\t\t\tMain Headquarters\t\t\t\t\t\t\t\n\n', '\n\n\n Founders\n\n\n\n\n\t\t\t\t\t\t\t\t\tThomas Lon Van\t\t\t\t\t\t\t\n\n', '\n\n\n Founder Diversity\n\n\n\n\n\t\t\t\t\t\t\t\t\tN/A\t\t\t\t\t\t\t\n\n', '\n\n\n Year Founded\n\n\n\n\n\t\t\t\t\t\t\t\t\t2016\t\t\t\t\t\t\t\n\n', '\n\n\n # of Employees\n\n\n\n\n\t\t\t\t\t\t\t\t\t1-10\t\t\t\t\t\t\t\n\n', '\n\n\n Seeking Funding?\n\n\n\n\n\t\t\t\t\t\t\t\t\tNo \t\t\t\t\t\t\t\n\n', '\n\n\n Funding Phase\n\n\n\n\n\t\t\t\t\t\t\t\t\tN/A\t\t\t\t\t\t\t\n\n'], ['\n\n\n Headquarters or Regional Office\n\n\n\n\n\t\t\t\t\t\t\t\t\tMain Headquarters\t\t\t\t\t\t\t\n\n', '\n\n\n Founders\n\n\n\n\n\t\t\t\t\t\t\t\t\tMacKenzie T Stout,\t\t\t\t\t\t\t\n\n', '\n\n\n Founder Diversity\n\n\n\n\n\t\t\t\t\t\t\t\t\tN/A\t\t\t\t\t\t\t\n\n', '\n\n\n Year Founded\n\n\n\n\n\t\t\t\t\t\t\t\t\t2020\t\t\t\t\t\t\t\n\n', '\n\n\n # of Employees\n\n\n\n\n\t\t\t\t\t\t\t\t\t1-10\t\t\t\t\t\t\t\n\n', '\n\n\n Seeking Funding?\n\n\n\n\n\t\t\t\t\t\t\t\t\tYes\t\t\t\t\t\t\t\n\n', '\n\n\n Funding Phase\n\n\n\n\n\t\t\t\t\t\t\t\t\tPre-Seed\t\t\t\t\t\t\t\n\n']]

我想使用正则表达式从输出中剥离\n\t\r，并以易于阅读的格式返回文本

这就是我尝试过的：

list_33 = []
for i in list_3:
     string = ''.join(list_3)
     list_33.append(re.sub('\s+','', string))
print(list_33)

输出：

['HeadquartersorRegionalOfficeMainHeadquarters', 'FoundersThomasLonVan', 'FounderDiversityN/A', 'YearFounded2016', '#ofEmployees1-10', 'SeekingFunding?No', 'FundingPhaseN/A']

这几乎是我所需要的，但我希望在列表3的第一个文本块之后，每个单词和冒号之间有一个空格，即：

['Headquarters or Regional Office: Main Headquarters', 'Founders: Thomas Lon Van', 'Founder Diversity: N/A', 'Year Founded: 2015', '# of Employees 1-10', 'Seeking Funding?: No', 'Funding Phase: N/A']

关于如何将两个正则表达式函数合并到一个正则表达式中，有什么想法吗

谢谢

---

另外，我知道对于只有一个元素的列表，我不需要使用for循环，但是将来列表中会有更多的元素，我现在正试图用一个输入来概括代码结构。

您可以浏览列表中的每个字符串，并使用

re.sub

用

替换每个出现的超过2个空格：

>>> import re
>>> lst = ['\n\n\n Headquarters or Regional Office\n\n\n\n\n\t\t\t\t\t\t\t\t\tMain Headquarters\t\t\t\t\t\t\t\n\n', '\n\n\n Founders\n\n\n\n\n\t\t\t\t\t\t\t\t\tThomas Lon Van\t\t\t\t\t\t\t\n\n', '\n\n\n Founder Diversity\n\n\n\n\n\t\t\t\t\t\t\t\t\tN/A\t\t\t\t\t\t\t\n\n', '\n\n\n Year Founded\n\n\n\n\n\t\t\t\t\t\t\t\t\t2016\t\t\t\t\t\t\t\n\n', '\n\n\n # of Employees\n\n\n\n\n\t\t\t\t\t\t\t\t\t1-10\t\t\t\t\t\t\t\n\n', '\n\n\n Seeking Funding?\n\n\n\n\n\t\t\t\t\t\t\t\t\tNo \t\t\t\t\t\t\t\n\n', '\n\n\n Funding Phase\n\n\n\n\n\t\t\t\t\t\t\t\t\tN/A\t\t\t\t\t\t\t\n\n']
>>> [re.sub(r'\s\s+', ': ', word).strip(': ') for word in lst]
['Headquarters or Regional Office: Main Headquarters', 'Founders: Thomas Lon Van', 'Founder Diversity: N/A', 'Year Founded: 2016', '# of Employees: 1-10', 'Seeking Funding?: No', 'Funding Phase: N/A']

---

您可以浏览列表中的每个字符串，并使用

re.sub

以

：

>>> import re
>>> lst = ['\n\n\n Headquarters or Regional Office\n\n\n\n\n\t\t\t\t\t\t\t\t\tMain Headquarters\t\t\t\t\t\t\t\n\n', '\n\n\n Founders\n\n\n\n\n\t\t\t\t\t\t\t\t\tThomas Lon Van\t\t\t\t\t\t\t\n\n', '\n\n\n Founder Diversity\n\n\n\n\n\t\t\t\t\t\t\t\t\tN/A\t\t\t\t\t\t\t\n\n', '\n\n\n Year Founded\n\n\n\n\n\t\t\t\t\t\t\t\t\t2016\t\t\t\t\t\t\t\n\n', '\n\n\n # of Employees\n\n\n\n\n\t\t\t\t\t\t\t\t\t1-10\t\t\t\t\t\t\t\n\n', '\n\n\n Seeking Funding?\n\n\n\n\n\t\t\t\t\t\t\t\t\tNo \t\t\t\t\t\t\t\n\n', '\n\n\n Funding Phase\n\n\n\n\n\t\t\t\t\t\t\t\t\tN/A\t\t\t\t\t\t\t\n\n']
>>> [re.sub(r'\s\s+', ': ', word).strip(': ') for word in lst]
['Headquarters or Regional Office: Main Headquarters', 'Founders: Thomas Lon Van', 'Founder Diversity: N/A', 'Year Founded: 2016', '# of Employees: 1-10', 'Seeking Funding?: No', 'Funding Phase: N/A']

---

Anad，感谢您的回复，我希望创建一个for循环，它将用于包含多个条目的列表。我已经更新了问题中的列表，它现在有两个条目，每个条目本身就是一个列表，因此原始的列表理解方法应该可以工作，但我看不出它如何转换为for循环，有什么想法吗？@AndrewLittle1

for I，lst in enumerate（list_3）：list_3[I]=[re.sub（…）for word in lst]

对于问题的正则表达式部分，我会将Prem的答案标记为正确，但非常感谢@Barmar帮助我设置答案的格式。感谢您的回复，我希望创建一个for循环，用于包含多个条目的列表。我已经更新了问题中的列表，它现在有两个条目，每个条目本身就是一个列表，因此原始的列表理解方法应该可以工作，但我看不出它如何转换为for循环，有什么想法吗？@AndrewLittle1

for I，lst in enumerate（list_3）：list_3[I]=[re.sub（…）for word in lst]

对于问题的正则表达式部分，我会将Prem的答案标记为正确，但非常感谢@Barmar帮助我设置答案格式