Python 连接列表视图和详细视图-django

Python 连接列表视图和详细视图-django,python,django,listview,django-views,detailsview,Python,Django,Listview,Django Views,Detailsview,我正在尝试创建基于类的详细视图,可以通过单击listview项来访问该视图。。问题是它在基于函数的视图中很容易实现,但在基于类的视图中却无法实现 model.py from django.db import models import datetime # Create your models here. class BlogPost(models.Model): title = models.CharField(max_length=500) writer = models.Ch

我正在尝试创建基于类的详细视图,可以通过单击listview项来访问该视图。。问题是它在基于函数的视图中很容易实现,但在基于类的视图中却无法实现

model.py

from django.db import models
import datetime
  # Create your models here.
   class BlogPost(models.Model):


title = models.CharField(max_length=500)
writer = models.CharField(max_length=150,default='my dept')
category =models.CharField(max_length=150)
image = models.ImageField(upload_to='images')
post   = models.TextField(max_length=2000)
Date  = models.DateField( default=datetime.date.today)


def __str__(self):
    return self.title
views.py

     from.models import BlogPost , EDITORIAL_RESPONSIBILITIES , Reviewers ,Confrences 
             ,ABSTRACT_IN_CONFERENCES
    class BlogList(ListView):
       model = BlogPost
      template_name = 'blog/bloglist.html'
         context_object_name = 'post'
   class BlogDetail(DetailView):
       model = BlogPost
          template_name = 'blogdetail.html'
url.py

path('list', BlogList.as_view(), name='list'),
path('(?P<id>\d+)/', BlogDetail.as_view())
path('list',BlogList.as_view(),name='list'),
路径(“(?P\d+/”,blogdail.as_view())
listview模板工作非常正常。。目录结构很好。。listviw.html和detail.html都位于templates/blog/下的同一文件夹中

列表视图模板

<div class="post-body">
                        {% for p in post %}
                        <blockquote>{{p}}</br></br>{{p.Date}}</blockquote>
                        {% endfor %}
                    </div><!-- end post-body -->

{post%%中的p的%s}
{{p}

{{p.Date} {%endfor%}
确保目录良好

templates
   --blog
     ---bloglist.html
     ---blogdetail.html
加上这个

class BlogDetail(DetailView):
   model = BlogPost
   template_name = 'blog/blogdetail.html'

def get_context_data(self, *args, **kwargs):
    context = super(BlogDetail, self).get_context_data(*args, **kwargs)
    post = self.get_object()
    context["post"] = post
    print(post)  #//To check if it's returning the right post
    return context
告诉我它是否有效

您说“目录结构很好..listviw.html和detail.html都在templates/blog/下的同一文件夹中”,因此,更改template_name='blog/blogdail.html'