Python 调用子类函数以减少代码复制
我希望通过在父类中使用公共代码来减少子类中的代码复制,但仍然需要执行一些特定的处理,这些处理会根据子类的不同而变化。我知道从父母那里给孩子打电话是不好的。如何完成代码缩减?(或者我应该试一试吗?) 这是一个例子:Python 调用子类函数以减少代码复制,python,class,reduction,Python,Class,Reduction,我希望通过在父类中使用公共代码来减少子类中的代码复制,但仍然需要执行一些特定的处理,这些处理会根据子类的不同而变化。我知道从父母那里给孩子打电话是不好的。如何完成代码缩减?(或者我应该试一试吗?) 这是一个例子: class Address: def __init__(self, street, city, postal_code): self._street = street self._city = city self._posta
class Address:
def __init__(self, street, city, postal_code):
self._street = street
self._city = city
self._postal_code = self.valid_postal_code(postal_code)
def valid_postal_code(self, postal_code):
""" Returns a validated postal code """
#
# A big bunch of code common to all postal codes
#
if child == Usa:
return Usa.valid_postal_code(postal_code)
else:
return Canada.valid_postal_code(postal_code)
class Usa(Address):
def valid_postal_code(self, postal_code):
""" Returns a validated US zip code """
# Must be 5 digits or 5 digits plus dash 4 digits
if len(postal_code) != 5 and len(postal_code) != 10:
raise Exception("Bad postal code")
return postal_code
class Canada(Address):
def valid_postal_code(self, postal_code):
""" Returns a validates Canadian postal code """
# Must be A#A #A#
if len(postal_code) == 6:
postal_code = postal_code[0:3] + " " + postal_code[3:3]
if len(postal_code) != 7:
raise Exception("Bad postal code")
return postal_code.upper()
每个重写方法都应该调用父方法
class Address:
def __init__(self, street, city, postal_code):
self._street = street
self._city = city
self._postal_code = self.valid_postal_code(postal_code)
def valid_postal_code(self, postal_code):
""" Returns a validated postal code """
#
# A big bunch of code common to all postal codes
#
...
class Usa(Address):
def valid_postal_code(self, postal_code):
""" Returns a validated US zip code """
# Must be 5 digits or 5 digits plus dash 4 digits
if not super().valid_postal_code(postal_code) or len(postal_code) != 5 and len(postal_code) != 10:
raise Exception("Bad postal code")
return postal_code
class Canada(Address):
def valid_postal_code(self, postal_code):
""" Returns a validates Canadian postal code """
# Must be A#A #A#
if len(postal_code) == 6:
postal_code = postal_code[0:3] + " " + postal_code[3:3]
if not super().valid_postal_code() or len(postal_code) != 7:
raise Exception("Bad postal code")
return postal_code.upper()
有两种可能性:
- 让父代码包含公共部分,子代码包含细节
- 父级必须返回中间结果
- 有两个父方法,其中一个是存根并由子方法重写
- 父级将中间结果传递到存根中
class Address:
def __init__(...):
def valid_postal_code(self, postal_code):
""" Returns a validated postal code """
#
# A big bunch of code common to all postal codes
#
return self._validate_postal_code(postal_code)
def _validate_postal_code(self, postal_code):
raise NotImplementedError
class Usa(Address):
def _validate_postal_code(self, postal_code):
""" Returns a validated US zip code """
# Must be 5 digits or 5 digits plus dash 4 digits
if len(postal_code) != 5 and len(postal_code) != 10:
raise Exception("Bad postal code")
return postal_code
class Canada(Address):
def _validate_postal_code(self, postal_code):
""" Returns a validates Canadian postal code """
# Must be A#A #A#
if len(postal_code) == 6:
postal_code = postal_code[0:3] + " " + postal_code[3:3]
if len(postal_code) != 7:
raise Exception("Bad postal code")
return postal_code.upper()
除了邮政编码之外,美国和加拿大的地址没有任何共同之处。基本上,
Address。有效的邮政编码
只有一个通用的占位符定义(如pass
或return True
或return False
),每个子类都必须用一个适当的定义覆盖它。让所有邮政编码共有的一大串代码成为一个公共部分,但是子类中应该保留不同的验证逻辑每个子类应该通过super()调用父类。有效的\u postal\u code()
而不是调用子实现的父类,因为父类不一定知道(或关心)哪些子类存在。