Python 如何停止守护进程线程或终止进程?
我有这个代码,我想在后台运行Python 如何停止守护进程线程或终止进程?,python,python-requests,python-daemon,Python,Python Requests,Python Daemon,我有这个代码,我想在后台运行 context.t = threading.Thread(target=psubscribe, args=[context, paramA, paramB, paramC], daemon=True) context.t.start() 这是正常的PSU订阅redis结果是某种通知 def psubscribe(context, paramA, paramB, paramC): context.test_config = load_config()
context.t = threading.Thread(target=psubscribe, args=[context, paramA, paramB, paramC], daemon=True)
context.t.start()
这是正常的PSU订阅redis结果是某种通知
def psubscribe(context, paramA, paramB, paramC):
context.test_config = load_config()
RedisConnector(context.test_config["redis_h"],
context.test_config["redis_db_"])
redis_subscriber_connector = RedisConnector(context.test_config["subscriber_redis_h"],
int(paramC),
int(context.test_config[
"subscriber_redis_p"]))
context.redis_connectors = redis_notification_subscribe.psubscribe_to_redis_event(paramA,
timeout_seconds=int(
paramB))
但是这个psubscribe每一步抛出一次结果,所以实际上是两个结果,我只需要一个。
如何停止守护进程发送PSU订阅