Python：简单对分搜索游戏中意外的条件激活

我写了一些代码来确定0到100之间的秘密号码。用户告诉机器猜测的数字（范围的一半）要么太高，要么太低，要么正好。根据输入，机器使用对分搜索来调整猜测。当猜测正确时，用户按c键，游戏结束。问题是，尽管在“我不理解输入”分支中设置了条件，但当用户按下c（有效条目）时，该分支会触发，而这不是第一次猜测

例如，以下是输出-

Please think of a number between 0 and 100!
Is your secret number 50?
Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. l
Is your secret number 75?
Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. c
Sorry, I did not understand your input.
Game over. Your secret number was:75
>>> 

    High=100
    Low=0
    Guess=50
    user_input=0

    print('Please think of a number between 0 and 100!')

    while user_input != 'c':
        print("Is your secret number"+" "+str(Guess)+"?")
        userinput = raw_input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly.")
        if user_input == 'h':
            High=Guess
            Guess= ((High+Low)/2)
        if user_input == 'l':
            Low=Guess
            Guess= ((High+Low)/2)
        if user_input != 'h' or 'l' or 'c':
            print('Sorry, I did not understand your input.')

    print ('Game over. Your secret number was:'''+ str(Guess))

下面是代码-

Please think of a number between 0 and 100!
Is your secret number 50?
Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. l
Is your secret number 75?
Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. c
Sorry, I did not understand your input.
Game over. Your secret number was:75
>>> 

    High=100
    Low=0
    Guess=50
    user_input=0

    print('Please think of a number between 0 and 100!')

    while user_input != 'c':
        print("Is your secret number"+" "+str(Guess)+"?")
        userinput = raw_input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly.")
        if user_input == 'h':
            High=Guess
            Guess= ((High+Low)/2)
        if user_input == 'l':
            Low=Guess
            Guess= ((High+Low)/2)
        if user_input != 'h' or 'l' or 'c':
            print('Sorry, I did not understand your input.')

    print ('Game over. Your secret number was:'''+ str(Guess))

---

提前谢谢。我已经为此绞尽脑汁好几个小时了……

条件句不是那样的。你需要像这样的东西：

# Check each condition explicitly
if user_input != 'h' and user_input != 'l' and user_input != 'c':

或：

您当前的方法被理解为

if (user_input != 'h') or ('l') or ('c'):

由于

l

和

c

是，所以该分支将始终执行

---

您也可以考虑使用<代码> ELIF < /C> >，因此您的条件将变成以下：

while True:
    if user_input == 'h':
        High=Guess
        Guess= ((High-Low)/2)
    elif user_input == 'l':
        Low=Guess
        Guess= ((High-Low)/2)
    elif user_input == "c":
        # We're done guessing. Awesome.
        break
    else:
        print('Sorry, I did not understand your input.')

---

用这个代替那个条件

if user_input not in ['h','l','c']:
      print('Sorry, I did not understand your input.')

您可能不必检查

user\u input

是否为

h

或

l

，因为前两个

if

应该处理这个问题

    if user_input == 'h':
        High=Guess
        Guess= ((High-Low)/2)
    elif user_input == 'l':
        Low=Guess
        Guess= ((High-Low)/2)
    elif user_input == 'c':
        pass # the while statement will deal with it or you could break
    else:
        print('Sorry, I did not understand your input.')

---

除了您的

if

，您的逻辑还有一些错误。我推荐如下：

High = 100
Low = 1
LastGuess = None

print('Please think of a number between 0 and 100!')

while True:
    Guess = int((High+Low)/2)
    if Guess == LastGuess:
        break
    print("Is your secret number"+" "+str(Guess)+"?")
    user_input = input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly.")
    if user_input == 'h':
        High = Guess
        LastGuess = Guess
    elif user_input == 'l':
        Low = Guess
        LastGuess = Guess
    elif user_input == 'c':
        break
    else:
        print('Sorry, I did not understand your input.')

print ('Game over. Your secret number was:'''+ str(Guess))

---

@uselpa哎哟，修好了。谢谢你的反馈。你能指出其他逻辑错误吗？猜测应该是（高+低）/2。而且，当程序不断猜测相同的数字时，您不会停止。此外，没有理由在多个位置计算Guess。您似乎使用Python 2，因此需要使用

raw\u input（）

，如示例所示。我使用了Python 3，这就是为什么我只使用

input（）

，但这也需要使用

int（）

来确保Guess是一个整数。好的，谢谢。我无意中用high-low粘贴了一个旧版本的代码，但是在多个地方的计算猜测是一个很好的观点，谢谢。谢谢你提供了关于条件的信息。我放弃了这个列表，因为我们在课堂上还没有达到他们的水平，我把猜测的计算加入了猜测本身。