Python 在plotly中更新特定子地块轴

设置：

import numpy as np
from plotly.subplots import make_subplots
from math import exp

fig = make_subplots(2, 1)

x = np.linspace(0, 10, 1000)
y = np.array(list(map(lambda x: 1 / (1 + exp(-0.1 * x + 5)), x)))
fig.add_trace(
    go.Scatter(
        x=x,
        y=y,
        name=f'\N{Greek Small Letter Sigma}(x)',
        showlegend=True
    ),
    row=1,
    col=1
)
fig.update_xaxes(title_text='x')
x = np.where(np.random.randint(0, 2, 100)==1)[0]
fig.add_trace(
    go.Scatter(
        x=x,
        y=np.zeros_like(x),
        name=f'Plot 2',
        mode='markers', 
        marker=dict(
                symbol='circle-open',
                color='green',
                size=5
            ),
        showlegend=True
    ),
    row=2,
    col=1
)
fig.update_xaxes(title_text='active users')
fig.show()

import numpy as np
from plotly.subplots import make_subplots
from math import exp

fig = make_subplots(2, 1)

x = np.linspace(0, 10, 1000)
y = np.array(list(map(lambda x: 1 / (1 + exp(-0.1 * x + 5)), x)))
fig.add_trace(
    go.Scatter(
        x=x,
        y=y,
        name=f'\N{Greek Small Letter Sigma}(x)',
        showlegend=True
    ),
    row=1,
    col=1
)
fig['layout']['xaxis'].update(title_text='x')

x = np.where(np.random.randint(0, 2, 100)==1)[0]
fig.add_trace(
    go.Scatter(
        x=x,
        y=np.zeros_like(x),
        name=f'Plot 2',
        mode='markers', 
        marker=dict(
                symbol='circle-open',
                color='green',
                size=5
            ),
        showlegend=True
    ),
    row=2,
    col=1
)
fig['layout']['xaxis2'].update(title_text='active users')

fig.show()

• 我正尝试使用

  plotly

  库绘制子地块，但不知道如何引用特定子地块的轴来更改其名称（或其他属性）
• 在

  code 1

  中，我展示了一个简单的示例，其中我使用

  plotly.subplot.make_subplot

  在另一个图的顶部添加了两个图

代码1

import numpy as np
from plotly.subplots import make_subplots
from math import exp

fig = make_subplots(2, 1)

x = np.linspace(0, 10, 1000)
y = np.array(list(map(lambda x: 1 / (1 + exp(-0.1 * x + 5)), x)))
fig.add_trace(
    go.Scatter(
        x=x,
        y=y,
        name=f'\N{Greek Small Letter Sigma}(x)',
        showlegend=True
    ),
    row=1,
    col=1
)

x = np.where(np.random.randint(0, 2, 100)==1)[0]
fig.add_trace(
    go.Scatter(
        x=x,
        y=np.zeros_like(x),
        name=f'Plot 2',
        mode='markers', 
        marker=dict(
                symbol='circle-open',
                color='green',
                size=5
            ),
        showlegend=True
    ),
    row=2,
    col=1
)
fig.show()

我所尝试的

我曾尝试在每次添加跟踪后使用

fig.update_xaxes（）

，但它会弄乱绘图，并且不会产生所需的输出，如

code 2

中所示

代码2:

import numpy as np
from plotly.subplots import make_subplots
from math import exp

fig = make_subplots(2, 1)

x = np.linspace(0, 10, 1000)
y = np.array(list(map(lambda x: 1 / (1 + exp(-0.1 * x + 5)), x)))
fig.add_trace(
    go.Scatter(
        x=x,
        y=y,
        name=f'\N{Greek Small Letter Sigma}(x)',
        showlegend=True
    ),
    row=1,
    col=1
)
fig.update_xaxes(title_text='x')
x = np.where(np.random.randint(0, 2, 100)==1)[0]
fig.add_trace(
    go.Scatter(
        x=x,
        y=np.zeros_like(x),
        name=f'Plot 2',
        mode='markers', 
        marker=dict(
                symbol='circle-open',
                color='green',
                size=5
            ),
        showlegend=True
    ),
    row=2,
    col=1
)
fig.update_xaxes(title_text='active users')
fig.show()

import numpy as np
from plotly.subplots import make_subplots
from math import exp

fig = make_subplots(2, 1)

x = np.linspace(0, 10, 1000)
y = np.array(list(map(lambda x: 1 / (1 + exp(-0.1 * x + 5)), x)))
fig.add_trace(
    go.Scatter(
        x=x,
        y=y,
        name=f'\N{Greek Small Letter Sigma}(x)',
        showlegend=True
    ),
    row=1,
    col=1
)
fig['layout']['xaxis'].update(title_text='x')

x = np.where(np.random.randint(0, 2, 100)==1)[0]
fig.add_trace(
    go.Scatter(
        x=x,
        y=np.zeros_like(x),
        name=f'Plot 2',
        mode='markers', 
        marker=dict(
                symbol='circle-open',
                color='green',
                size=5
            ),
        showlegend=True
    ),
    row=2,
    col=1
)
fig['layout']['xaxis2'].update(title_text='active users')

fig.show()

这会导致（注意顶部打印的

活动用户

）：

我的问题：

import numpy as np
from plotly.subplots import make_subplots
from math import exp

fig = make_subplots(2, 1)

x = np.linspace(0, 10, 1000)
y = np.array(list(map(lambda x: 1 / (1 + exp(-0.1 * x + 5)), x)))
fig.add_trace(
    go.Scatter(
        x=x,
        y=y,
        name=f'\N{Greek Small Letter Sigma}(x)',
        showlegend=True
    ),
    row=1,
    col=1
)
fig.update_xaxes(title_text='x')
x = np.where(np.random.randint(0, 2, 100)==1)[0]
fig.add_trace(
    go.Scatter(
        x=x,
        y=np.zeros_like(x),
        name=f'Plot 2',
        mode='markers', 
        marker=dict(
                symbol='circle-open',
                color='green',
                size=5
            ),
        showlegend=True
    ),
    row=2,
    col=1
)
fig.update_xaxes(title_text='active users')
fig.show()

import numpy as np
from plotly.subplots import make_subplots
from math import exp

fig = make_subplots(2, 1)

x = np.linspace(0, 10, 1000)
y = np.array(list(map(lambda x: 1 / (1 + exp(-0.1 * x + 5)), x)))
fig.add_trace(
    go.Scatter(
        x=x,
        y=y,
        name=f'\N{Greek Small Letter Sigma}(x)',
        showlegend=True
    ),
    row=1,
    col=1
)
fig['layout']['xaxis'].update(title_text='x')

x = np.where(np.random.randint(0, 2, 100)==1)[0]
fig.add_trace(
    go.Scatter(
        x=x,
        y=np.zeros_like(x),
        name=f'Plot 2',
        mode='markers', 
        marker=dict(
                symbol='circle-open',
                color='green',
                size=5
            ),
        showlegend=True
    ),
    row=2,
    col=1
)
fig['layout']['xaxis2'].update(title_text='active users')

fig.show()

如何将标签

x

分配给顶部打印x轴，将

活动用户

标签分配给底部打印的x轴

一般来说，如何访问单个子地块的属性

谢谢你的帮助。提前感谢。

在我的帮助下，我可以通过参考

行=1

位置上的绘图的

xaxis

，

col=1

和

行=2

位置上的绘图的

xaxis1

来解决这个问题。完整的解决方案在

代码1

中

代码1:

import numpy as np
from plotly.subplots import make_subplots
from math import exp

fig = make_subplots(2, 1)

x = np.linspace(0, 10, 1000)
y = np.array(list(map(lambda x: 1 / (1 + exp(-0.1 * x + 5)), x)))
fig.add_trace(
    go.Scatter(
        x=x,
        y=y,
        name=f'\N{Greek Small Letter Sigma}(x)',
        showlegend=True
    ),
    row=1,
    col=1
)
fig.update_xaxes(title_text='x')
x = np.where(np.random.randint(0, 2, 100)==1)[0]
fig.add_trace(
    go.Scatter(
        x=x,
        y=np.zeros_like(x),
        name=f'Plot 2',
        mode='markers', 
        marker=dict(
                symbol='circle-open',
                color='green',
                size=5
            ),
        showlegend=True
    ),
    row=2,
    col=1
)
fig.update_xaxes(title_text='active users')
fig.show()

import numpy as np
from plotly.subplots import make_subplots
from math import exp

fig = make_subplots(2, 1)

x = np.linspace(0, 10, 1000)
y = np.array(list(map(lambda x: 1 / (1 + exp(-0.1 * x + 5)), x)))
fig.add_trace(
    go.Scatter(
        x=x,
        y=y,
        name=f'\N{Greek Small Letter Sigma}(x)',
        showlegend=True
    ),
    row=1,
    col=1
)
fig['layout']['xaxis'].update(title_text='x')

x = np.where(np.random.randint(0, 2, 100)==1)[0]
fig.add_trace(
    go.Scatter(
        x=x,
        y=np.zeros_like(x),
        name=f'Plot 2',
        mode='markers', 
        marker=dict(
                symbol='circle-open',
                color='green',
                size=5
            ),
        showlegend=True
    ),
    row=2,
    col=1
)
fig['layout']['xaxis2'].update(title_text='active users')

fig.show()

---

干杯。

fig.layout

比

fig['layout']

稍微安全一些。