在connexion旁边使用python相对导入是否有特定的语法？

我目前正在尝试使用connexion构建api。但是，我在使用通过connexion模块的相对本地模块导入时遇到了一些问题，这会修改基础flask应用程序。以下是我的文件结构的简化概述：

• 名人堂
  • 控制器
    • ____初始值
    • routes.py
  • 模型
    • ____初始值
    • routes.py
  • ____初始值
  • config.py
  • 创建_db.py
  • 昂首阔步

尝试在终端中运行“python config.py”时出错。下面是config.py：

import os
import connexion
from flask_sqlalchemy import SQLAlchemy
from flask_marshmallow import Marshmallow

basedir = os.path.abspath(os.path.dirname(__file__))

# Create the Connexion application instance
connex_app = connexion.App(__name__, specification_dir=basedir)

# Get the underlying Flask app instance
app = connex_app.app
connex_app.add_api('swagger.yml')

# Configure the SQLAlchemy part of the app instance
app.config['SQLALCHEMY_ECHO'] = True
app.config['SQLALCHEMY_DATABASE_URI'] = 'postgresql://doadmin:password@nba-player-db-do-user-7027314-0.db.ondigitalocean.com:25060/nba_test_1?sslmode=require'
app.config['SQLALCHEMY_TRACK_MODIFICATIONS'] = False

# Create the SQLAlchemy db instance
db = SQLAlchemy(app)

# Initialize Marshmallow
ma = Marshmallow(app)

下面是它给出的错误：

Failed to add operation for GET /api/players
Failed to add operation for GET /api/players
Traceback (most recent call last):
  File "/usr/local/lib/python3.7/site-packages/connexion/apis/abstract.py", line 209, in add_paths
self.add_operation(path, method)
  File "/usr/local/lib/python3.7/site-packages/connexion/apis/abstract.py", line 173, in add_operation
    pass_context_arg_name=self.pass_context_arg_name
  File "/usr/local/lib/python3.7/site-packages/connexion/operations/__init__.py", line 8, in make_operation
    return spec.operation_cls.from_spec(spec, *args, **kwargs)
  File "/usr/local/lib/python3.7/site-packages/connexion/operations/swagger2.py", line 137, in from_spec
    **kwargs
  File "/usr/local/lib/python3.7/site-packages/connexion/operations/swagger2.py", line 96, in __init__
    pass_context_arg_name=pass_context_arg_name
  File "/usr/local/lib/python3.7/site-packages/connexion/operations/abstract.py", line 96, in __init__
    self._resolution = resolver.resolve(self)
  File "/usr/local/lib/python3.7/site-packages/connexion/resolver.py", line 40, in resolve
    return Resolution(self.resolve_function_from_operation_id(operation_id), operation_id)
  File "/usr/local/lib/python3.7/site-packages/connexion/resolver.py", line 66, in resolve_function_from_operation_id
    raise ResolverError(str(e), sys.exc_info())
connexion.exceptions.ResolverError: <ResolverError: module 'controller.routes' has no attribute 'read_all'>

现在我很困惑，因为我的routes.py文件确实有一个定义为read_all（）的函数，下面是该文件：

from model.models import Regseason, RegSchema, Playoffs, PlayoffSchema

def read_all():

    return Regseason.query.all()

---

我已经为这个错误绞尽脑汁了将近24小时，任何指导都将不胜感激。提前谢谢

请在operationid下面添加一个额外字段x-openapi-router-controller。Connexion使用它映射要向哪个模块发送请求。它与OperationId结合在一起，以转到正确的模块和功能。

您可以链接这些路线吗？您在swagger文件中设置了一个基本路径“/api”，但Get请求会删除“/api/players”。如果您的flask路由看起来像“/api/players”，那么结果将是端点为“/api/api/players”。我实际上还没有添加任何路由，但我确实明白您的意思！我可能不应该将该文件命名为routes.py，我将修复命名约定，但您看到的最后一段代码是routes.py，我无法重现您的问题，但我相信这是由于PYTHONPATH造成的。尝试执行：

PYTHONPATH=。yourCommand

@KevinMartins我到底要用什么替换yourCommand？目录的路径？@HenryBowe

PYTHONPATH=。python config.py

from model.models import Regseason, RegSchema, Playoffs, PlayoffSchema

def read_all():

    return Regseason.query.all()