Python 如何将非类型转换为int?
您好,我得到了2个结果385和3025,但当我想减去这两个结果时,我得到了一个错误,我如何才能将none类型转换为integer您无法从Python 如何将非类型转换为int?,python,Python,您好,我得到了2个结果385和3025,但当我想减去这两个结果时,我得到了一个错误,我如何才能将none类型转换为integer您无法从none中获得int值。相反,使用从函数中获得的int值。更改此项: def kareler(x:int,y:int): toplam=0 for i in range(x,y): toplam+=i**2 return toplam def tkareler(x:int,y:int): toplam1=0
none
中获得int值。相反,使用从函数中获得的int值。更改此项:
def kareler(x:int,y:int):
toplam=0
for i in range(x,y):
toplam+=i**2
return toplam
def tkareler(x:int,y:int):
toplam1=0
for i in range(x,y):
toplam1+=i
return toplam1**2
sayi1=print(kareler(1,11))
sayi2=print(tkareler(1,11))
print("Gerekli sayi",sayi2-sayi1) # TypeError: unsupported operand type(s) for -: 'NoneType' and 'NoneType'
if type(sayi1)==None:
sayi1=int(sayi1)
print(sayi1) # this even not give any result to me
为此:
sayi1=print(kareler(1,11))
sayi2=print(tkareler(1,11))
print
函数返回None
,而不是您告诉它要打印的内容 print()函数始终返回None。不用打印就说1=kareler(1,11)。哦,好吧,我知道了,非常感谢。这意味着当我想得到整数形式的函数结果时,我不应该写,我应该写函数名并赋值给variableYes;一般来说,您键入的确切内容很重要。:)向一行代码中添加额外的内容通常会改变它的工作方式。
sayi1 = kareler(1,11)
sayi2 = tkareler(1,11)
print(f"{sayi1}/n{sayi2}")