Python 存储文本文件中出现的每个单词的计数

我想将文本文件中出现的每个单词的计数存储在字典中。我是说

fob= open('D:/project/report.txt','r')

我可以将这些行存储到列表中，但我需要将这些行拆分为单个单词，并最终存储它们的计数（就像在附加数据中一样）

---

我该怎么做？什么是有效的方法呢？

对于Python

2.7+

from collections import Counter

with open('D:/project/report.txt','r') as fob:
    c = Counter(word for line in fob for word in line.split())

对于Python

2.5+

from collections import defaultdict
dd = defaultdict(int)

with open('D:/project/report.txt','r') as fob:
    for line in fob:
        for word in line.split():
            dd[word] += 1

对于较老的蟒蛇或讨厌

defaultdict

d = {}

with open('D:/project/report.txt','r') as fob:
    for line in fob:
        for word in line.split():
            d[word] = d.get(word, 0) + 1

---

对于Python

2.7+

from collections import Counter

with open('D:/project/report.txt','r') as fob:
    c = Counter(word for line in fob for word in line.split())

对于Python

2.5+

from collections import defaultdict
dd = defaultdict(int)

with open('D:/project/report.txt','r') as fob:
    for line in fob:
        for word in line.split():
            dd[word] += 1

对于较老的蟒蛇或讨厌

defaultdict

d = {}

with open('D:/project/report.txt','r') as fob:
    for line in fob:
        for word in line.split():
            d[word] = d.get(word, 0) + 1