python中的eror不支持/：'str'和'int'的操作数类型

我在Python中遇到了这个错误

我应该做什么来修复错误

我的程序是用Tkinter编写的

如果你能解决我的问题，谢谢你

from tkinter import *    
def Diagnosis():        
    get1 =  inp.get()
    if get1 / 2 == '0':
        Label(windows,font = 'IranNastaliq',text = 'عدد زوج است').pack()
    else:
        Label(windows,font = 'IranNastaliq',text = 'عدد فرد است ').pack()
   
windows = Tk()
windows.geometry('500x600')
windows.configure(bg ='aqua')
windows.maxsize(500,600)
windows.minsize(400,500)

inp = Entry(windows,font ='IranNastaliq' )
inp.pack()

windows.title("icc-aria gui app")

btn = Button(windows)

btn.configure(text="تایید",font = ('IranNastaliq',14),command = Diagnosis )

btn.pack()

windows.mainloop()

---

将输入转换为int或float：

from tkinter import *    
def Diagnosis():        
    get1 =  int(inp.get())
    if get1 / 2 == 0:
        Label(windows,font = 'IranNastaliq',text = 'عدد زوج است').pack()
    else:
        Label(windows,font = 'IranNastaliq',text = 'عدد فرد است ').pack()
   
windows = Tk()
windows.geometry('500x600')
windows.configure(bg ='aqua')
windows.maxsize(500,600)
windows.minsize(400,500)

inp = Entry(windows,font ='IranNastaliq' )
inp.pack()

windows.title("icc-aria gui app")

btn = Button(windows)

btn.configure(text="تایید",font = ('IranNastaliq',14),command = Diagnosis )

btn.pack()

windows.mainloop()

---

从错误消息中，听起来像inp.get返回字符串

您可以将其转换为整数：

def诊断： get1=inp.get 如果intget1/2==0： Labelwindows，字体='IranNastaliq'，文本='IranNastaliq'。打包 其他： Labelwindows，字体='IranNastaliq'，文本='IranNastaliq'.'

---

可能会执行get1=intinp.get或get1=floatinp.get不客气。