Python 如何检测列表项的特定值何时更改，并通过与相应项的映射将索引捕获到字典中

我的清单如下：

['24', '24', '24', '24', '24', '1D', '1D', '1D', **'1D'**, **'24'**, '24', '24', '1D', '1D','24','24']

我希望检测项目何时从

'1D'

更改为

'24'

，并将项目映射到相应的索引

如本例所示，输出应如下所示：

{“1d”：[8,13]，“24”：[9,14]}

这就是你想要的吗

A = ['24', '24', '24', '24', '24', '1D', '1D', '1D', '1D', '24', '24', '24', '1D', '1D','24','24']
res = [[A[i], A[i + 1]] for i in range(len(A) - 1)] 
B = [index for index, value in enumerate(res) if value == ['1D','24']]
B
[8, 13] # feel free to add 1 if want to shift it to the second element position.

编辑： 解决方案使用：

更多阅读资料：

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谢谢@s.k。我还需要索引值8,9,13,14，并将该值映射到它们的索引，如{1d:[8,13]，24:[9,14]}您最好改进您的问题，以全面地包含此功能。；-）我已经更新了问题@s.k

import numpy as np
A = ['24', '24', '24', '24', '24', '1D', '1D', '1D', '1D', '24', '24', '24', '1D', '1D','24','24']
sequence = ['1D','24']
# get all sequences
res = [[A[i], A[i + 1]] for i in range(len(A) - 1)]
# find index of such sequence
B = np.array([[i,i+1] for i, v in enumerate(res) if v == sequence]).T

# create an dict with sequences elements as keys and their 
# values as list of indexes:
mydict = {sequence[i]: list(B[i]) for i in range(len(sequence))} 


>>> mydict
{'1D': [8, 13], '24': [9, 14]}