Python-Flask-pass图像URL而不是文件

我使用Python 3.6.5-Flask 0.12.2获得了这段代码，公开了一个服务并接收图像文件：

@app.route('/image', methods=['POST'])
def image():
    try:
        image_file = request.files['image']  # get the image

        # Set an image confidence threshold value to limit returned data
        threshold = request.form.get('threshold')
        if threshold is None:
            threshold = 0.5
        else:
            threshold = float(threshold)

        # finally run the image through tensor flow object detection`
        image_object = Image.open(image_file)
        objects = od_ws_api.get_objects(image_object, threshold)
        return objects

    except Exception as e:
        print(e)

当我使用这个CURL命令运行程序时，一切正常：

curl -F "image=@xxx.jpg" http://localhost:5000/image

我的目标是使用相同的POST方法传递图像URL，而不是本地文件，如：

curl -F "image=https://i.ytimg.com/vi/aeLgjgoy_kE/maxresdefault.jpg" http://localhost:5000/image

如果我这样做，我会收到以下错误消息：

400 Bad Request: The browser (or proxy) sent a request that this server could not understand.
127.0.0.1 - - [10/Apr/2018 08:20:52] "POST /image HTTP/1.1" 200

我应该使用其他方法还是库？ 非常感谢。 雷格斯

---

我确实修改为：

@app.route('/image_url', methods=['POST'])
def image_url():
    try:
        image_url = request.value['image_url']  # get the image URL
        local_filename='c:/tensorflow/temp.jpg'
        local_filename, headers = urllib.request.urlretrieve(image_url)
        # Set an image confidence threshold value to limit returned data
        threshold = request.form.get('threshold')
        if threshold is None:
            threshold = 0.5
        else:
            threshold = float(threshold)

        # finally run the image through tensor flow object detection`
        image_object = Image.open(image_file)
        objects = od_ws_api.get_objects(image_object, threshold)
        return objects

    except Exception as e:
        print(e)
        return 'error'

在字符串卷曲之后：

curl -F "image_url=@https://i.ytimg.com/vi/aeLgjgoy_kE/maxresdefault.jpg" http://localhost:5000/image_url

我收到以下错误：

Warning: setting file https://i.ytimg.com/vi/aeLgjgoy_kE/maxresdefault.jpg
Warning: failed!
curl: (26) read function returned funny value

---

如果将curl与文件名一起使用，它将不会存储在

request.files

中，而是存储在

request.values

中。因此，要获取图像url，您需要调用

image_url = request.value['image']

现在您需要下载图像，例如使用：

---

图像现在存储在一个临时文件中，您可以通过

本地\u文件名访问该文件

我确实修改了该方法以使其正常工作：

import requests
@app.route('/image_url', methods=['GET'])
def image_url():
    try:
        f = open('c:/tensorflow1/temp.jpg','wb')
        image_url = request.args['image_url']  # get the image URL
        f.write(requests.get(image_url).content)
        f.close()
        # Set an image confidence threshold value to limit returned data
        threshold = request.form.get('threshold')
        if threshold is None:
            threshold = 0.5
        else:
            threshold = float(threshold)

        # finally run the image through tensor flow object detection`
        image_object = Image.open('c:/tensorflow1/temp.jpg')
        objects = od_ws_api.get_objects(image_object, threshold)
        return objects

    except Exception as e:
        print(e)
        return 'error'

现在我使用了简单的CURL命令：

curl http://localhost:5000/image_url?image_url=https://i.ytimg.com/vi/aeLgjgoy_kE/maxresdefault.jpg

而且它有效！

---

谢谢您的帮助

您是否尝试过前面没有https的图像URL？是的，但它不起作用您好，很抱歉我的帖子有点乱。基本上我已经按照上面所述进行了修改，但在临时文件中检索图像时仍然有问题。您尝试打开远程图像文件。将

image\u object=image.open（image\u file）

替换为

image\u object=image.open（local\u filename）

完成，但更改后我收到此错误：127.0.0.1---[10/Apr/2018 14:15:11]“POST/image\u url HTTP/1.1”200-“Request”对象没有属性“value”

curl http://localhost:5000/image_url?image_url=https://i.ytimg.com/vi/aeLgjgoy_kE/maxresdefault.jpg