使用python将HTTP请求行发送到jupyter

我试图在如下模块的帮助下向我的jupyter笔记本发送HTTP请求：

with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
    s.connect(('127.0.0.1', 8888))
    s.sendall(b'GET /api/contents HTTP/1.1 \n\n') # Maybe i didn't understand how HTTP requests work
    print(s.recv(1024))

输出（在jupyter笔记本运行的终端中）：

收到的数据是HTTP/1.1400错误请求\r\n\r\n

它说它使用这个分隔符

re.compile（b'\r？\n\r？\n'）

---

如果您不想在

HTTP

请求中提供任何头，只需按

\r\n\r\n

顺序终止它即可：

s.sendall(b'GET /api/contents HTTP/1.1\r\n\r\n')

HTTP

使用

\r\n

序列作为行分隔符（如在Windows中）和双序列（

\r\n\r\n

）来标记请求头的结束。所以通常请求看起来像

GET /api/contents HTTP/1.1\r\n
User-Agent: blablah\r\n
....\r\n
\r\n
<HERE GOES REQUEST BODY>

GET/api/contents HTTP/1.1\r\n
用户代理：blablah\r\n
....\r\n
\r\n

GET /api/contents HTTP/1.1\r\n
User-Agent: blablah\r\n
....\r\n
\r\n
<HERE GOES REQUEST BODY>