Python 来自txt文件程序的字数

我正在用以下代码计算txt文件的字数：

#!/usr/bin/python
file=open("D:\\zzzz\\names2.txt","r+")
wordcount={}
for word in file.read().split():
    if word not in wordcount:
        wordcount[word] = 1
    else:
        wordcount[word] += 1
print (word,wordcount)
file.close();

这给了我这样的输出：

>>> 
goat {'goat': 2, 'cow': 1, 'Dog': 1, 'lion': 1, 'snake': 1, 'horse': 1, '': 1, 'tiger': 1, 'cat': 2, 'dog': 1}

但我希望以以下方式输出：

word  wordcount
goat    2
cow     1
dog     1.....

---

我还在输出中得到一个额外的符号（

ï»

）。如何删除此项？

您遇到的有趣符号是UTF-8。要消除它们，请使用正确的编码打开文件（我假设您使用的是Python 3）：

此外，对于计数，您可以使用：

将它们显示为：

>>> for item in wordcount.items(): print("{}\t{}".format(*item))
...
snake   1
lion    2
goat    2
horse   3

---

如果您使用的是graphLab，则可以使用此函数。它真的很强大

products['word_count'] = graphlab.text_analytics.count_words(your_text)

# 您可以这样做：

file= open(r'D:\\zzzz\\names2.txt')
file_split=set(file.read().split())
print(len(file_split))

下面的代码是为我工作的

 import re
    frequency = {}
    #Open the sample text file in read mode.
    document_text = open('sample.txt', 'r')
    #convert the string of the document in lowercase and assign it to text_string variable.
    text = document_text.read().lower()
    pattern = re.findall(r'\b[a-z]{2,15}\b', text)
    for word in pattern:
         count = frequency.get(word,0)
         frequency[word] = count + 1
     frequency_list = frequency.keys()
     for words in frequency_list:
         print(words, frequency[words])

输出：

---

看看。你的python版本是什么？你可以在@user3068762检查示例有效性：关于AttributeError:“dict”对象没有属性“key”：wordcount.keys（）中的key的行应该是错误的：——注意

workcount.keys

中的key后面的“s”字符返回此文件，而不是第一个参数。我看不出这是你想要的。修改您的答案。请添加一些解释。但是如何对它们进行排序？如果您解释了您提供的代码如何回答问题，这将是一个更好的答案。请解释您的解决方案如何以及您的解决方案如何/为什么比现有的解决方案更好/不同。

#!/usr/bin/python
file=open("D:\\zzzz\\names2.txt","r+")
wordcount={}
for word in file.read().split():
    if word not in wordcount:
        wordcount[word] = 1
    else:
        wordcount[word] += 1
for k,v in wordcount.items():
    print k, v

products['word_count'] = graphlab.text_analytics.count_words(your_text)

FILE_NAME = 'file.txt'

wordCounter = {}

with open(FILE_NAME,'r') as fh:
  for line in fh:
    # Replacing punctuation characters. Making the string to lower.
    # The split will spit the line into a list.
    word_list = line.replace(',','').replace('\'','').replace('.','').lower().split()
    for word in word_list:
      # Adding  the word into the wordCounter dictionary.
      if word not in wordCounter:
        wordCounter[word] = 1
      else:
        # if the word is already in the dictionary update its count.
        wordCounter[word] = wordCounter[word] + 1

print('{:15}{:3}'.format('Word','Count'))
print('-' * 18)

# printing the words and its occurrence.
for  (word,occurance)  in wordCounter.items(): 
  print('{:15}{:3}'.format(word,occurance))

    Word           Count
    ------------------
    of               6
    examples         2
    used             2
    development      2
    modified         2
    open-source      2

#!/usr/bin/python
file=open("D:\\zzzz\\names2.txt","r+")
wordcount={}
for word in file.read().split():
    if word not in wordcount:
        wordcount[word] = 1
    else:
        wordcount[word] += 1

for k,v in wordcount.items():
    print k,v
file.close();

file= open(r'D:\\zzzz\\names2.txt')
file_split=set(file.read().split())
print(len(file_split))

 import re
    frequency = {}
    #Open the sample text file in read mode.
    document_text = open('sample.txt', 'r')
    #convert the string of the document in lowercase and assign it to text_string variable.
    text = document_text.read().lower()
    pattern = re.findall(r'\b[a-z]{2,15}\b', text)
    for word in pattern:
         count = frequency.get(word,0)
         frequency[word] = count + 1
     frequency_list = frequency.keys()
     for words in frequency_list:
         print(words, frequency[words])

print("sorted counting values:-")
from collections import Counter

fname = open(filename)

fname = fname.read()

fsplit = fname.split()

user  = Counter(fsplit)

for i,v in sorted(user.items()):

   print((v,i))