Python2.7：这个程序有什么问题？它运行，但奇怪的回溯错误

程序运行良好。但是用这个截图。它只是一片空白。它的Python 2.7。我还将Python添加到了环境变量中，但shell上也没有显示任何内容

石头布和剪刀代码 错误：

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回溯最近的调用上次：文件 C:/Users/Sarthak/Desktop/RPS.py，第80行，在 如果名称='main'：名称错误：未定义名称'name'

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您应该修复缩进和所有其他错误：

import random
import time

rock = 1
paper = 2
scissors = 3

names = { rock: "Rock" , paper: "Paper" , scissors: "Scissors" }
rules = { rock: scissors , paper :rock , scissors: paper }

player_score = 0
computer_score = 0

def start():

    print "Let's play a game of rock paper and scissors"
    while game():
        pass
    scores()


def game():
    player = move()
    computer = random.randint(1,3)
    result(player, computer)
    return play_again()

def move():
    while True:
        print #this is not how you could get int input in Python
        player = raw_int("Rock = 1\nPaper = 2\nScissors =3\nMake a move: ")

        try:
            player = int(player)
            if player in (1,2,3):
                return player
        except ValueError:
            pass
        print "Oops! I didn't understand that. Please enter 1,2 or 3." #note the indentation here

def result(player, computer):
    print "1..."
    time.sleep(1)
    print "2..."
    time.sleep(1)
    print "3..."
    time.sleep(0.5)

    print "Computer threw {0)!".format(names[computer])

    global player_score,computer_score

    if player == computer:
        print "Tie game."


    else:
        if rules[player] == computer:
            print "Your victory has been assured."
            player_score += 1

        else:
            print" The computer laughs as you realise you have been defeated."
            computer_score += 1


def play_again(): #again, indentation
    #and this is not how you could get string input in Python
    answer = raw_input("Would you like to play again? y/n: ")
    if answer in ("Y", "Y" , "yes" , "Yes" , "Of course!"):
        return answer
    else:
        print "Thank you very much for playing our game.See your next time!"

def scores(): #note the indentation here
    global player_score,computer_score
    print "High Scores"
    print "Player:" , player_score
    print "Computer:", computer_score

if __name__ == '__main__': #note the underscores here
  start()

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我是Python新手。如何呼叫start？我确实打过电话。但是还有一个错误，uni-dented与外部缩进级别不匹配，正如回答者所示，您可以将start粘贴在程序的底部。@BHouwens我确实将它粘贴在了底部。但是，还有一个错误，Unidented与外部标识级别不匹配。@SarthakBhatia在程序的底部调用它，并且在底部不提供任何缩进all@BHouwens现在有一个最近的回溯调用last:File C:/Users/Sarthak/Desktop/RPS.py，第80行，在if name='main'：name错误：name'name'未定义您的if\u name\u='\uu main\uuu'未正确缩进，现在它在您的分数范围内function@MaxNoe谢谢，现在它运行了，但有一个回溯错误。在上面添加了屏幕截图。回溯最近的通话最后：文件C:/Users/Sarthak/Desktop/RPS.py，第80行，在if name='main'：name错误：name'name'未定义请建议一个…-这个问题与您的主要问题完全无关。通常，我会告诉您为每个新主题创建一个新问题，但这种问题在“禁止主题4”页面中被明确列为非主题，所以请删除它。将准确地告诉您要去哪里。请不要编辑您的问题以包含新问题。相反，创建一个新问题。我还建议您在提出下一个问题之前阅读，因为您似乎还没有掌握有关堆栈溢出问题的一些规则。

import random
import time

rock = 1
paper = 2
scissors = 3

names = { rock: "Rock" , paper: "Paper" , scissors: "Scissors" }
rules = { rock: scissors , paper :rock , scissors: paper }

player_score = 0
computer_score = 0

def start():

    print "Let's play a game of rock paper and scissors"
    while game():
        pass
    scores()


def game():
    player = move()
    computer = random.randint(1,3)
    result(player, computer)
    return play_again()

def move():
    while True:
        print #this is not how you could get int input in Python
        player = raw_int("Rock = 1\nPaper = 2\nScissors =3\nMake a move: ")

        try:
            player = int(player)
            if player in (1,2,3):
                return player
        except ValueError:
            pass
        print "Oops! I didn't understand that. Please enter 1,2 or 3." #note the indentation here

def result(player, computer):
    print "1..."
    time.sleep(1)
    print "2..."
    time.sleep(1)
    print "3..."
    time.sleep(0.5)

    print "Computer threw {0)!".format(names[computer])

    global player_score,computer_score

    if player == computer:
        print "Tie game."


    else:
        if rules[player] == computer:
            print "Your victory has been assured."
            player_score += 1

        else:
            print" The computer laughs as you realise you have been defeated."
            computer_score += 1


def play_again(): #again, indentation
    #and this is not how you could get string input in Python
    answer = raw_input("Would you like to play again? y/n: ")
    if answer in ("Y", "Y" , "yes" , "Yes" , "Of course!"):
        return answer
    else:
        print "Thank you very much for playing our game.See your next time!"

def scores(): #note the indentation here
    global player_score,computer_score
    print "High Scores"
    print "Player:" , player_score
    print "Computer:", computer_score

if __name__ == '__main__': #note the underscores here
  start()