Python 如何使此程序忽略标点符号

我是python新手，我不知道如何让这个程序忽略标点符号；我知道这真的很低效，但我现在并不为此烦恼

while True:
y="y"
n="n"

Sentence=input("Please enter your sentence: ").upper()
print("Your sentence is:",Sentence)
Correct=input("Is your sentence correct? y/n ")
if Correct==n:
    break
elif Correct==y:
    Location=0

    SplitSentence = Sentence.split(" ")
    for word in SplitSentence:
        locals()[word] = Location
        Location+=1
    print("")

    FindWord=input("What word would you like to search? ").upper()
    if FindWord not in SplitSentence:
        print("Your chosen word is not in your sentence")
    else:
        iterate=0
        WordBank=[]
        for word in SplitSentence:
            iterate=iterate+1
            if word == FindWord: 
                WordBank.append(iterate) 
        print(FindWord, WordBank) 

    break

---

非常感谢您能给我的任何帮助。您可以使用Python的

字符串
模块帮助测试标点符号

>> import string
>> print string.punctuation
!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~
>> sentence = "I am a sentence, and; I haven't been punctuated well.!"

请注意，“have not”中的撇号已被删除，这是完全忽略标点符号的副作用。
您只想删除所有内容，而不是：a-zA-Z0-9，或者您是否设置了要测试的标点符号？
>> cleaned_sentence = ''.join([c for c in sentence if c not in string.punctuation])
>> print cleaned_sentence
'I am a sentence and I havent been punctuated well'