在python中对正则表达式匹配中的唯一值进行排序
我正在尝试解析日志文件以提取电子邮件地址。 我能够匹配电子邮件并在正则表达式的帮助下打印它。 我注意到我的日志文件中有两封重复的电子邮件。你能帮我弄清楚如何删除重复项并根据匹配的模式只打印唯一的电子邮件地址吗 以下是我迄今为止编写的代码：在python中对正则表达式匹配中的唯一值进行排序,python,regex,string-parsing,Python,Regex,String Parsing,我正在尝试解析日志文件以提取电子邮件地址。 我能够匹配电子邮件并在正则表达式的帮助下打印它。 我注意到我的日志文件中有两封重复的电子邮件。你能帮我弄清楚如何删除重复项并根据匹配的模式只打印唯一的电子邮件地址吗 以下是我迄今为止编写的代码： import sys import re file = open('/Users/me/Desktop/test.txt', 'r') temp =[] for line in file.readlines(): if '->' in line
import sys
import re
file = open('/Users/me/Desktop/test.txt', 'r')
temp =[]
for line in file.readlines():
if '->' in line:
temp = line.split('->')
elif '=>' in line:
temp = line.split('=>')
if temp:
#temp[1].strip()
pattern = re.match('^\x20\w{1,}@\w{1,}\.\w{2,3}\x20?', str(temp[1]), re.M)
if pattern is not None:
print pattern.group()
else:
print "nono"
提前感谢。您可以使用
集合import sys
import re
file = open('/Users/me/Desktop/test.txt', 'r')
temp =[]
seen = set()
for line in file.readlines():
if '->' in line:
temp = line.split('->')
elif '=>' in line:
temp = line.split('=>')
if temp:
#temp[1].strip()
pattern = re.match('^\x20\w{1,}@\w{1,}\.\w{2,3}\x20?', str(temp[1]), re.M)
if pattern is not None:
matched = pattern.group()
if matched not in seen:
print matched
else:
print "nono"
from __future__ import print_function
import re
with open('test.txt') as f:
data = f.read().splitlines()
emails = set(re.sub(r'^.*\s+(\w+\@[^\s]*?)\s+.*', r'\1', line) for line in data if '@' in line)
print('\n'.join(emails)) if len(emails) else print('nono')
lol@somedomain.com
me@somedomain.com
someuser@somedomain.com
wo@somedomain.com
PS您可能需要进行适当的电子邮件RegExp检查，因为我使用了非常原始的检查一些重复项是由于代码中的错误造成的，您在处理每一行时没有重置
temp->=>if temp:->=>continue集import sys
import re
addresses = set()
pattern = re.compile('^\x20\w{1,}@\w{1,}\.\w{2,3}\x20?')
with open('/Users/me/Desktop/test.txt', 'r') as f:
for line in f:
if '->' in line:
temp = line.split('->')
elif '=>' in line:
temp = line.split('=>')
else:
# neither '=>' nor '->' present in the line
continue
match = pattern.match(temp[1])
if match is not None:
addresses.add(match.group())
else:
print "nono"
for address in sorted(addresses):
print(address)
withimport re
addresses = set()
pattern = re.compile(r'[-=]> +(\w{1,}@\w{1,}\.\w{2,3})')
with open('test.txt', 'r') as f:
for line in f:
match = pattern.search(line)
if match:
addresses.add(match.groups()[0])
for address in sorted(addresses):
print(address)
您可以将结果存储在
集合中集合中