如何在Python中对2D数组进行非连续切片
我的朋友A回来了,她现在看起来像如何在Python中对2D数组进行非连续切片,python,arrays,numpy,Python,Arrays,Numpy,我的朋友A回来了,她现在看起来像 A = np.array([ [0,1,1,1,0,0,0,0], [1,0,0,1,0,0,0,0], [1,0,0,1,0,0,0,0], [1,1,1,0,0,0,0,0], [0,0,0,1,0,1,0,0], [0,0,0,0,1,0,1,1], [0,0,0,0,0,1,0,1], [0,0,0,0,0,1,1,0], ]) 我需要找到子矩阵H=A[(1,3
A = np.array([
[0,1,1,1,0,0,0,0],
[1,0,0,1,0,0,0,0],
[1,0,0,1,0,0,0,0],
[1,1,1,0,0,0,0,0],
[0,0,0,1,0,1,0,0],
[0,0,0,0,1,0,1,1],
[0,0,0,0,0,1,0,1],
[0,0,0,0,0,1,1,0],
])
我需要找到子矩阵H=A[(1,3,7),(2,3,6)]
。但这是回报
array([0, 0, 1])
我希望第1、3和7行与第2、3和6列成对出现。我似乎找不到那个语法
H = [[0,1,0],
[1,0,0],
[0,0,1]]
您可以使用:
啊!我忘了。谢谢
A[np.ix_((1,3,7),(2,3,6))]
#array([[0, 1, 0],
# [1, 0, 0],
# [0, 0, 1]])