Python 在django中将函数修饰符转换为类Mixin

我试图将cutoms装饰器从一个函数转换为一个类Mixin，因为我使用CVB，我想从这个Mixin继承来检查一些页面的用户状态。我有一个decorator，它检查用户是否经过身份验证，如果用户经过身份验证并尝试访问具有该decorator的页面，它将重定向到仪表板，如果没有，则il将有权访问该页面。我将该类作为装饰器的类版本编写，如果用户已登录，则该类正常工作，但如果用户未登录并尝试访问该页面，则会出现以下错误：

在/auth/login处配置不正确/ UserLoginView缺少所需的权限属性。定义UserLoginView.permission\u required，或覆盖UserLoginView.get\u permission\u required（）

这是装饰师：

def is_authenticated(view_func):
    def wrapper_func(request, *args, **kwargs):
        if request.user.is_authenticated:
            return redirect('dashboard')
        else:
            return view_func(request, *args, **kwargs)
    return wrapper_func

类别版本：

class IsAuthenticatedMixin(PermissionRequiredMixin):
    def dispatch(self, request, *args, **kwargs):
        if request.user.is_authenticated:
            return redirect('dashboard')
        return super().dispatch(request, *args, **kwargs)

继承此mixin的视图

class IndexFormView(IsAuthenticatedMixin, CreateView):
    permission_required = 'view'
    template_name = 'home/index.html'
    form_class = NewsletterForm

    def post(self, request, *args, **kwargs):
        email = request.POST['email']
        if Newsletter.objects.filter(email=email).exists():
            messages.warning(
                request, 'This email is already subscribed in our system')
        else:
            Newsletter.objects.create(
                email=email)
            messages.success(request,
                             'Your email was subscribed in our system, you\'ll hear from us as soon as possible !')
        return super().post(request, *args, **kwargs)

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        context['testimonials'] = Testimonial.objects.order_by('-created_date')[:9]
        return context


class AboutTemplateView(IsAuthenticatedMixin, TemplateView):
    template_name = 'home/about.html'

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        context['banner_page_title'] = 'About Us'
        context['page_location'] = 'home / about'
        return context

class UserResgistrationCreateView(IsAuthenticatedMixin, CreateView):
    template_name = 'home/auth/register.html'
    form_class = UserRegistrationForm
    success_url = reverse_lazy('login')


class UserLoginView(IsAuthenticatedMixin, LoginView):
    template_name = 'home/auth/login.html'

---

发生这种情况的原因是，您从中创建了子类，这意味着在使用

IsAuthenticatedMixin

的所有视图中，都需要提供

permission\u required

类属性。此处的错误与用户登录视图有关：

class UserLoginView(IsAuthenticatedMixin, LoginView):
    template_name = 'home/auth/login.html'
    permission_required = …

在需要使用权限的视图中，还可以将

PermissionRequiredMixin子类化：

from django.contrib.auth.mixins import PermissionRequiredMixin

class IndexFormView(IsAuthenticatedMixin, PermissionRequiredMixin, CreateView):
    permission_required = 'view'
    template_name = 'home/index.html'
    form_class = NewsletterForm
来自django.contrib.auth.mixin导入权限RequiredMixin
类IndexFormView（IsAuthenticatedMixin、PermissionRequiredMixin、CreateView）：
权限\所需='查看'
模板名称='home/index.html'
非常感谢，这是非常有用的信息。我会改变我的混音并测试它！！
from django.contrib.auth.mixins import PermissionRequiredMixin

class IndexFormView(IsAuthenticatedMixin, PermissionRequiredMixin, CreateView):
    permission_required = 'view'
    template_name = 'home/index.html'
    form_class = NewsletterForm