Python BeautifulSoup用“填写缺失信息”；不适用；不起作用

我正在以下网站上练习我的网页抓取技能：“

到目前为止，我掌握的代码如下。看起来我得到的公司计数是正确的，但我的CSV文件中有重复的行，我认为每当公司丢失信息时就会出现这种情况。在我的代码的多个部分中，我试图检测缺失的信息并用文本“N/A”替换，但它不起作用。我猜这个问题可能与Zip（）函数有关，但我不确定如何修复它

非常感谢您的帮助

"""
Grabs brewery name, contact person, phone number, website address, and email address 
for each brewery listed on the website.
"""

import requests, csv
from bs4 import BeautifulSoup

url = "http://web.californiacraftbeer.com/Brewery-Member"
res = requests.get(url)
soup = BeautifulSoup(res.content, "lxml")
each_company = soup.find_all("div", {"class": "ListingResults_All_CONTAINER ListingResults_Level3_CONTAINER"})
error_msg = "N/A" 

def scraper():
    """Grabs information and writes to CSV"""
    print("Running...")
    results = []
    count = 0

    for info in each_company:
        try:
            company_name = info.find_all("span", itemprop="name")
        except Exception as e:
            company_name = "N/A"
        try:
            contact_name = info.find_all("div", {"class": "ListingResults_Level3_MAINCONTACT"})
        except Exception as e:
            contact_name = "N/A"
        try:
            phone_number = info.find_all("div", {"class": "ListingResults_Level3_PHONE1"})
        except Exception as e:
            phone_number = "N/A"
        try:
            website = info.find_all("span", {"class": "ListingResults_Level3_VISITSITE"})
        except Exception as e:
            website = "N/A"

        for company, contact, phone, site in zip(company_name, contact_name, phone_number, website):
            count += 1
            print("Grabbing {0} ({1})...".format(company.text, count))
            newrow = []
            try:
                newrow.append(company.text)
            except Exception as e:
                newrow.append(error_msg)
            try:
                newrow.append(contact.text)
            except Exception as e:
                newrow.append(error_msg)
            try:
                newrow.append(phone.text)
            except Exception as e:
                newrow.append(error_msg)
            try:
                newrow.append(site.find('a')['href'])
            except Exception as e:
                newrow.append(error_msg)
            try:
                newrow.append("info@" + company.text.replace(" ", "").lower() + ".com")
            except Exception as e:
                newrow.append(error_msg)
        results.append(newrow)

    print("Done")
    outFile = open("brewery.csv", "w")
    out = csv.writer(outFile, delimiter=',',quoting=csv.QUOTE_ALL, lineterminator='\n')
    out.writerows(results)
    outFile.close()

def main():
    """Runs web scraper"""
    scraper()

if __name__ == '__main__':
    main()

从

如果find_all（）找不到任何内容，它将返回一个空列表。如果 find（）找不到任何内容，它返回None“

因此，例如，当

company\u name=info.find\u all（“span”，itemprop=“name”）

运行并且不匹配任何内容时，它不会抛出异常，并且不会设置

“NA”

在这种情况下，您需要检查

公司名称

是否为空列表：

if not company_name:
    company_name = "N/A"