Python 提高背景资料的覆盖率MOG2和findContours

Python 提高背景资料的覆盖率MOG2和findContours,python,python-2.7,opencv,Python,Python 2.7,Opencv,我试图用固定摄像机在足球场上追踪球员。背景MOG2和findContours导致检测到大量小轮廓。我如何更改BackgroundSubtractorMOG2/findContours的结果,以便一个形状(一个玩家)产生一个轮廓,我可以跟踪 这是我使用的代码: import numpy as np import cv2 cap = cv2.VideoCapture("images/Keeper.mov") history = 30 # or whatever you want it to b

我试图用固定摄像机在足球场上追踪球员。背景MOG2和findContours导致检测到大量小轮廓。我如何更改BackgroundSubtractorMOG2/findContours的结果,以便一个形状(一个玩家)产生一个轮廓,我可以跟踪

这是我使用的代码:

import numpy as np
import cv2

cap = cv2.VideoCapture("images/Keeper.mov")
history = 30   # or whatever you want it to be
accelerate = 5

kernel = cv2.getStructuringElement(cv2.MORPH_ELLIPSE,(3,3))
        fgbg = cv2.BackgroundSubtractorMOG2()

while(1):
    for i in (1, accelerate):
        ret, frame = cap.read()

    fgmask = fgbg.apply(frame, learningRate=1.0/history)

    fgmask = cv2.morphologyEx(fgmask, cv2.MORPH_OPEN, kernel)
    cv2.imshow('frame',fgmask)

    h, w = fgmask.shape[:2]

    contours0, hierarchy = cv2.findContours( fgmask.copy(),
                       cv2.RETR_TREE, cv2.CHAIN_APPROX_SIMPLE)
    contours = [cv2.approxPolyDP(cnt, 3, True) for cnt in contours0]

    vis = np.zeros((h, w, 3), np.uint8)
    levels = 17
    cv2.drawContours( vis, contours, (-1, 3)[levels <= 0],
                      (128,255,255),-1, cv2.CV_AA, hierarchy, abs(levels) )
    cv2.imshow('contours', vis)

    k = cv2.waitKey(30) & 0xff
    if k == 27:
        break

cap.release()
cv2.destroyAllWindows()
将numpy导入为np
进口cv2
cap=cv2.VideoCapture(“images/Keeper.mov”)
历史=30#或你想要的任何东西
加速=5
kernel=cv2.getStructuringElement(cv2.MORPH_ELLIPSE,(3,3))
fgbg=cv2.BackgroundSubtractorMOG2()
而(一):
对于(1)中的i,加速:
ret,frame=cap.read()
fgmask=fgbg.apply(帧,学习率=1.0/历史)
fgmask=cv2.morphologyEx(fgmask,cv2.MORPH_OPEN,kernel)
cv2.imshow(“帧”,fgmask)
h、 w=fgmask.shape[:2]
轮廓0,hierarchy=cv2.findContours(fgmask.copy(),
cv2.RETR_树,cv2.CHAIN_近似值(简单)
轮廓=[cv2.approxPolyDP(cnt,3,True)表示轮廓0中的cnt]
vis=np.zero((h,w,3),np.uint8)
级别=17

cv2.drawContours(vis,contours,(-1,3)[级别通常通过“放大”或“闭合”形态学操作来完成,但您应该显示一些图像来清楚说明这一点。@Miki Explation效果很好,谢谢