Python 如何在数组中搜索单词，如果找到，如何将相应的字符串返回到全局变量？

我对Python非常陌生。 我想查看字符串数组，如果某些单词匹配，则将这些单词作为变量返回。我希望能够在全局范围内打印if语句之外的变量

fullsubject = cells[2].text.encode("utf-8").replace(",","")
subs = fullsubject.split(' ')
# the above two lines work fine.

下面是subs数组的一些示例（我想在其中查找单词）：

如果数组包含“MANH”或“Manhattan”，我希望变量borough等于“MANH”。
如果数组包含“QNS”或“queen”，我希望borough等于“QNS”。
如果数组包含“BX”或“Bronx”，我希望borough等于“BX”

首先我试着这样做：

global borough
for item in subs:
    if item == "BX":
        borough = "BX"
    elif item == "QNS":
        borough = "QNS"
    else:
        borough = "something else"
print borough

borough = []
if [item for item in subs if item=="BX" or "Bronx"]:
    borough.append("BX")
elif [item for item in subs if item=="QNS" or "Queens"]:
    borough.append("QNS")
elif [item for item in subs if item=="MANH"]:
    borough.append("MANH")
elif [item for item in subs if item=="BKLYN" or "Brooklyn"]:
    borough.append("BKLYN")
elif [item for item in subs if item=="STATEN" or "SI"]:
    borough.append("SI")
print borough

string_list = ['list', 'of', 'words', 'MANH']
borough = word_check(string_list)

但它总是打印最后一个选项“其他内容”。
然后我想也许我可以这样做：

global borough
for item in subs:
    if item == "BX":
        borough = "BX"
    elif item == "QNS":
        borough = "QNS"
    else:
        borough = "something else"
print borough

borough = []
if [item for item in subs if item=="BX" or "Bronx"]:
    borough.append("BX")
elif [item for item in subs if item=="QNS" or "Queens"]:
    borough.append("QNS")
elif [item for item in subs if item=="MANH"]:
    borough.append("MANH")
elif [item for item in subs if item=="BKLYN" or "Brooklyn"]:
    borough.append("BKLYN")
elif [item for item in subs if item=="STATEN" or "SI"]:
    borough.append("SI")
print borough

string_list = ['list', 'of', 'words', 'MANH']
borough = word_check(string_list)

但我还是得到了最后一个选择

---

我已搜索堆栈溢出，但找不到正确答案。帮助？

您只需检查您的单词是否在列表中。比较中不需要列表来检查某个内容是否正确。然后返回变量

def word_check(string_list):
    for word in string_list:
        if word == "BX" or word == "Bronx":
            borough = "BX"
        elif word == "QNS" or word == "Queens":
            borough = "QNS"
        elif word == "MANH":
            borough = "MANH"
        else:
            borough = "something else"
    return borough

然后你这样称呼它：

global borough
for item in subs:
    if item == "BX":
        borough = "BX"
    elif item == "QNS":
        borough = "QNS"
    else:
        borough = "something else"
print borough

borough = []
if [item for item in subs if item=="BX" or "Bronx"]:
    borough.append("BX")
elif [item for item in subs if item=="QNS" or "Queens"]:
    borough.append("QNS")
elif [item for item in subs if item=="MANH"]:
    borough.append("MANH")
elif [item for item in subs if item=="BKLYN" or "Brooklyn"]:
    borough.append("BKLYN")
elif [item for item in subs if item=="STATEN" or "SI"]:
    borough.append("SI")
print borough

string_list = ['list', 'of', 'words', 'MANH']
borough = word_check(string_list)

---

你好你能给我们举一个你正在使用的字符串数组的例子，也许还有你试图匹配的单词？谢谢你好@NBlaine-我添加了更多细节。谢谢对不起，我不清楚。我遇到的问题是，我希望能够访问该函数之外的borough变量。我更新了我的问题，使之更具体。你可以让它全球化，但你不需要。只需在函数末尾返回变量。这仅在单词是数组中的最后一项时有效。