如何使用python将枚举文档与原始文档合并？

首先，我想列举一个包含两个以上句子的文档，如下所示：

doc = """I like movie. But I don't like the cast. The story is very nice"""
doc1 = doc.split('.')
list = []
for i in enumerate(doc1):
     list.append(i)

对于每个句子，我都会找到一个情绪分数，然后我希望通过平均分数将枚举文档合并到原始格式

如有任何答复，将不胜感激

doc2 = """I like movie. But I don't like the cast. The story is very nice"""

---

我不确定我是否真的理解了你的问题

请注意，您的代码相当于：

doc = """I like movie. But I don't like the cast. The story is very nice"""
doc1 = doc.split('.')
result = list(enumerate(doc1))

（我使用了

result

，因为

list

会隐藏我用来构建列表的名称

list

）

如果你把

doc = """I like movie. But I don't like the cast. The story is very nice"""

作为输入，您将获得

结果

值

result = [(0,"I like movie"),(1," But I don't like the cast"),(2," The story is very nice")]

注意字符串开头的空格。它可能是你想要的，也可能不是

基本结果 如果您的问题是“如何在给定结果的情况下重新创建初始字符串？”，下面是一个示例代码：

recreated_doc = ".".join(value for index, value in result)

高级答案 请注意，如果您提供

doc = """I like movie. But I don't like the cast. The story is very nice."""

使用结尾逗号，您将得到：

result = [(0,"I like movie"),(1," But I don't like the cast"),(2," The story is very nice"),(3,"")]

但是如果我想换成下一行呢

result = [(0,"I like movie"),(1,"But I don't like the cast"),(2,"The story is very nice")]

（请注意，字符串的开头没有空格，也没有空字符串。）

代码如下：

doc = """I like movie. But I don't like the cast. The story is very nice."""
doc1 = doc.split('.')
doc2 = (part.strip(' ') for part in doc1)
doc3 = (part for part in doc2 if len(part) > 0)
result = list(enumerate(doc3))
# result = [(0, 'I like movie'), (1, "But I don't like the cast"), (2, 'The story is very nice')]

并重新创建原始字符串：

recreated_doc = " ".join(value+"." for index, value in result)
# recreated_doc = """I like movie. But I don't like the cast. The story is very nice."""

警告，高级解决方案并不总是重新创建相同的原始文档，因此可能无法执行

例如：

doc = """This a document with a lot of spaces.   .   Too much spaces here.       And also here     .   ."""
# [...]
# recreated_doc = """This a document with a lot of spaces. Too much spaces here. And also here."""

---

你能举一个你想要的输出的例子吗：“第二，我想把列举的文档合并成原始格式。”？输出应该像原始文档“doc1”一样，我不确定我是否在这方面跟你一样-如果你有权访问原始文档及其内容，你为什么要重新构建它？我正在为每个句子找到分数，然后我想通过取平均值将其合并到原始文档中。从中加入很简单：

。。。。加入（j代表uu，j在列表中）

谢谢@gissehel。这就是我所期望的“重新创建的_doc=“.”。join（索引的值，结果中的值）