python使用urllib2和urllib get请求问题
当我使用curl-get-request成功,但使用python调用get-request失败时,任何人都可以提供帮助python使用urllib2和urllib get请求问题,python,api,get,urllib,urllib2,Python,Api,Get,Urllib,Urllib2,当我使用curl-get-request成功,但使用python调用get-request失败时,任何人都可以提供帮助 shell script: curl -X GET -H 'Content-type: application/json' -H 'Authorization: Bearer '$token'' -d '[ { "id":"535985", "language":"EN", "Detailes":{"LibraryId":"KF_2gl9xZYKX7TJi66" }, "Key
shell script:
curl -X GET -H 'Content-type: application/json' -H 'Authorization: Bearer '$token'' -d '[ { "id":"535985", "language":"EN", "Detailes":{"LibraryId":"KF_2gl9xZYKX7TJi66" }, "KeyID":"SF_cY1tKhYiocNluBB" } ]' 'https://XXXX.com'
获取请求成功
python Script:
data ={ "id":"535985", "language":"EN", "Detailes":{"LibraryId":"KF_2gl9xZYKX7TJi66" }, "KeyID":"SF_cY1tKhYiocNluBB" }
headers = {'content-type': 'application/json', 'Accept': 'application/json', 'Authorization': 'Bearer %s' % (token)}
proxy = urllib2.ProxyHandler({})
opener = urllib2.build_opener(proxy)
urllib2.install_opener(opener)
DataForGet=urllib.urlencode(data)
NewUrl= apilink + "?" + DataForGet
request = urllib2.Request(NewUrl, headers)
response = urllib2.urlopen(request, timeout=300)
message = response.read()
返回消息
TypeError:不可损坏的类型
任何人都知道如何通过urllib2和urllib模型使用get请求。非常感谢 我发现我们可以定义这个方法来调用api获取数据
class RequestMethod(urllib2.Request,object):
def __init__(self, url, method=None,data=None, headers={},origin_req_host=None, unverifiable=False):
self.method = method
super(RequestMethod,self).__init__(url, data=data,headers=headers,origin_req_host=origin_req_host,unverifiable=unverifiable)
def get_method(self):
if self.method != None:
return self.method
else:
return super(RequestMethod,self).get_method()
def set_method(self,method):
self.method = method
def setMethodRequest(url,method):
return RequestMethod(url,method=method)
为什么不使用?因为服务器python版本是2.7,我们没有访问pip安装请求模型的权限。请将您的问题包含在完整的回溯中。