Python 通过从列表中获取值，基于列值动态删除熊猫中的数据帧行
如何转换以下代码Python 通过从列表中获取值，基于列值动态删除熊猫中的数据帧行,python,pandas,Python,Pandas,如何转换以下代码 list_of_things = [0,1,2,3,4...] df = df[df.line_race != 0] 如果line_race中的值在_事物列表中，我知道我可以很容易地通过循环实现这一点，但如果能得到帮助，我宁愿不要，通过转换数据帧使其动态化 daysago line_race rating rw wrating line_date
list_of_things = [0,1,2,3,4...]
df = df[df.line_race != 0]
daysago line_race rating rw wrating
line_date
2007-03-31 62 11 56 1.000000 56.000000
2007-03-10 83 11 67 1.000000 67.000000
2007-02-10 111 9 66 1.000000 66.000000
2007-01-13 139 10 83 0.880678 73.096278
2006-12-23 160 10 88 0.793033 69.786942
2006-11-09 204 9 52 0.636655 33.106077
2006-10-22 222 8 66 0.581946 38.408408
2006-09-29 245 9 70 0.518825 36.317752
2006-09-16 258 11 68 0.486226 33.063381
2006-08-30 275 8 72 0.446667 32.160051
2006-02-11 475 5 65 0.164591 10.698423
2006-01-13 504 0 70 0.142409 9.968634
2006-01-02 515 1 64 0.134800 8.627219
2005-12-06 542 2 70 0.117803 8.246238
2005-11-29 549 0 70 0.113758 7.963072
2005-11-22 556 1 -1 0.109852 -0.109852
2005-11-01 577 0 -1 0.098919 -0.098919
2005-10-20 589 0 -1 0.093168 -0.093168
2005-09-27 612 1 -1 0.083063 -0.083063
2005-09-07 632 0 -1 0.075171 -0.075171
2005-06-12 719 1 69 0.048690 3.359623
2005-05-29 733 3 -1 0.045404 -0.045404
2005-05-02 760 0 -1 0.039679 -0.039679
2005-04-02 790 2 -1 0.034160 -0.034160
2005-03-13 810 1 -1 0.030915 -0.030915
2004-11-09 934 0 -1 0.016647 -0.016647
df = df[~df.line_race.isin(list_of_things)]