Python 试着把摩尔斯电码翻译成英语

我正在用我用的字典把摩尔斯电码翻译成英语。我试图让它在用户输入信息的地方，它会将他/她的信息打印成莫尔斯电码

我发现翻译成摩尔斯电码很容易，然而把摩尔斯电码翻译成英语给了我一些问题

首先，如果我为'A'键入'.-'我实际上得到的是'E'，因为它读取的是第一个'.'键，并将其转换为'E'而不是整个字符串

这就是我迄今为止所尝试的：）

这是我的字典

morse_eng_dict = {".-": "A", "-...": "B", "-.-.": "C", "-..": "D", ".": "E",
                  "..-.": "F", "--.": "G", "....": "H",
                  "..": "I", ".---": "J", "-.-": "K", ".-..": "L",
                  "--": "M", "-.": "N", "---": "O", ".--.": "P",
                  "--.-": "Q", ".-.": "R", "...": "S", "-": "T", "..-": "U", "...-": "V",
                  ".--": "W", "-..-": "X", "-.--": "Y", "--..": "Z"}

我想让Python把我的摩尔斯电码打印成英文。比如说…-…-…-（这是你好）

这是一个项目，所以我不能使用任何花哨的模块或任何东西。

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有什么想法或意见吗？谢谢大家!

莫尔斯电码是由模糊性构成的。正如你所指出的。-可以被视为e t或a。如果不借助大词典或模糊逻辑，就无法轻松区分它们

运算符倾向于使用空格分隔字母和单词，但是：

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“一个单词的字母之间用等于三个点（一个破折号）的空格分隔，单词之间用等于七个点的空格分隔。”如果你在莫尔斯电码串中插入空格，例如：字母之间的空格为1，单词之间的空格为2，这将使解码变得轻而易举（拆分然后映射）

类似的方法应该会奏效： 基本上，当有空格时，它会分割字符串，生成一个列表，其中每个项目都是摩尔斯电码字母。然后，它根据字典检查每个字母，并取对应的英文字母。最后，它将所有这些内容放入一个列表中，再次将其转换为字符串并打印出来。 希望有帮助

morse_eng_dict = {".-": "A", "-...": "B", "-.-.": "C", "-..": "D", ".": "E",
"..-.": "F", "--.": "G", "....": "H",
"..": "I", ".---": "J", "-.-": "K", ".-..": "L",
"--": "M", "-.": "N", "---": "O", ".--.": "P",
"--.-": "Q", ".-.": "R", "...": "S", "-": "T", "..-": "U", "...-": "V",
".--": "W", "-..-": "X", "-.--": "Y", "--..": "Z"}

nomorse = input("Enter your Morse code here:")
nomorse_list = nomorse.split() #this splits the string up wherever there is a space
not_morse = []
morse = True    #The code is morse (so far)
for letter in nomorse_list:
    eng_letter = False
    for key in morse_eng_dict.keys():   #for each of the morse code letters in the dictionary
        if letter == key:
            eng_letter = morse_eng_dict[key]
    if eng_letter: #if a letter was found that corresponds
        not_morse.append(eng_letter)
    else:
        print("Input is not valid morse code.")
        morse = False
if morse == True:
    string = "".join(not_morse) #joining the string together (without spaces in between)
    print(string)

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对于任何

dictionary={.-：'a'}

字典['.-']会给你“a” 还有dictionary.get（“.-”）也会给你一个“a” 字典的索引是字符串，任何字符串，“.”与“.-”不同

","一","一","一","一",

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顺便说一句，莫尔斯是一个二叉树，以E=left.node和T=right.node开头…

可能是重复的哦，非常感谢！对不起

morse_eng_dict = {".-": "A", "-...": "B", "-.-.": "C", "-..": "D", ".": "E",
"..-.": "F", "--.": "G", "....": "H",
"..": "I", ".---": "J", "-.-": "K", ".-..": "L",
"--": "M", "-.": "N", "---": "O", ".--.": "P",
"--.-": "Q", ".-.": "R", "...": "S", "-": "T", "..-": "U", "...-": "V",
".--": "W", "-..-": "X", "-.--": "Y", "--..": "Z"}

nomorse = input("Enter your Morse code here:")
nomorse_list = nomorse.split() #this splits the string up wherever there is a space
not_morse = []
morse = True    #The code is morse (so far)
for letter in nomorse_list:
    eng_letter = False
    for key in morse_eng_dict.keys():   #for each of the morse code letters in the dictionary
        if letter == key:
            eng_letter = morse_eng_dict[key]
    if eng_letter: #if a letter was found that corresponds
        not_morse.append(eng_letter)
    else:
        print("Input is not valid morse code.")
        morse = False
if morse == True:
    string = "".join(not_morse) #joining the string together (without spaces in between)
    print(string)