Python 如何在yaml文件中搜索特定字符串和内容

下面是我的yaml文件

    filename:
      #Name of the JMX files which needs to be executed
      - URLLogin.txt
      - URLupload.txt
      - XlsxFileUpload.txt

    URLLogin:
      - this is to test the script

    XlsxFileUpload:
      - this is to test the current script

我将把文件名存储在一个数组中。并调用一个方法来获取循环中的文件描述。如果文件名有描述，则应返回1，否则应返回零

下面是我搜索描述的代码

#this method is to search a particular string in yaml
def searchStringInYaml(filename,string):
    with open(filename, 'r') as stream:
        content = yaml.load(stream)
        if string in content:
            print string
            return 1
        else:
            return 0
    stream.close()

yaml.load（stream）

返回dict use

content.items（）

以迭代并检查值

Ex:

import yaml
with open(filename, 'r') as stream:
    content = yaml.load(stream)
    for k,v in content.items():
        if "URLLogin.txt" in v:
            print k, v

filename ['URLLogin.txt', 'URLupload.txt', 'XlsxFileUpload.txt']

输出：

import yaml
with open(filename, 'r') as stream:
    content = yaml.load(stream)
    for k,v in content.items():
        if "URLLogin.txt" in v:
            print k, v

filename ['URLLogin.txt', 'URLupload.txt', 'XlsxFileUpload.txt']

---

如果您只需要检查yaml文件中的指定字符串，请不要解析yaml文件。只需阅读文件并检查内容

def searchStringInYaml(filename,string):
    with open(filename) as f:
        contents = f.read()
        return string in contents

---

yaml.load

返回字典。上校不是凯普托凯。如果删除冒号，则无法搜索字符串。它只返回零总是@cricket_007

内容中的字符串

只检查字典的键，没有任何值显示来检查值@不清楚你在找什么。您是绝对需要解析yaml，还是只需要检查文件是否包含

字符串

？如果是后者，则可以

返回1 If string in open（filename）.read（）else 0