str对象不可调用错误python
我一直在尝试用Python运行以下代码:str对象不可调用错误python,python,Python,我一直在尝试用Python运行以下代码: def likes(names): dictionary_of_sizes = { 0:"no one likes this", 1:(lambda names: "{} likes this".format(names[0])), 2:(lambda names: "{} and {} like this".format(names[0], names[1])), 3:(lamb
def likes(names):
dictionary_of_sizes = {
0:"no one likes this",
1:(lambda names: "{} likes this".format(names[0])),
2:(lambda names: "{} and {} like this".format(names[0], names[1])),
3:(lambda names: "{}, {} and {} like this".format(name[0], names[1],names[2])),
4:(lambda names: "{}, {} and {} others like this".format(names[0], names[1], len(names)-2))
}
return dictionary_of_sizes[len(names)](names) if len(names)<4 else dictionary_of_sizes[4]
def类(名称):
字典大小={
0:“没人喜欢这个”,
1:(lambda名称:“{}喜欢这个”。格式(名称[0]),
2:(lambda名称:“{}和{}类似于此”。格式(名称[0],名称[1]),
3:(lambda名称:“{},{}和{}类似于此”。格式(名称[0],名称[1],名称[2]),
4:(lambda名称:“{},{}和{}其他类似的名称”。格式(名称[0],名称[1],len(名称)-2))
}
返回大小为[len(names)](names)的字典(如果len(names)如果传递空字符串,它将写出错误消息。
您可以使用列表而不是字典:
def likes(names):
options = ["no one likes this",
lambda names: "{} likes this".format(names[0]),
lambda names: "{} and {} like this".format(names[0], names[1]),
lambda names: "{}, {} and {} like this".format(name[0], names[1],names[2]),
lambda names: "{}, {} and {} others like this".format(names[0], names[1], len(names)-2)
]
if type(names) == list:
return options[min(len(options),len(names))](names)
使用Python 3.6的f字符串:
产出:
您没有向我们显示引发异常的代码。当你不告诉我们你在做什么的时候,很难说出你做错了什么。但如果我这样做,它似乎会起作用:
>>> likes(["John","Harry"])
'John and Harry like this'
我怀疑您可能会这样调用likes()
:
>>> likes(["John","Harry"])()
Traceback (most recent call last):
File "<input>", line 1, in <module>
TypeError: 'str' object is not callable
>>> likes("")
Traceback (most recent call last):
File "<input>", line 1, in <module>
File "<input>", line 7, in likes
TypeError: 'str' object is not callable
到
但是你真的应该放弃那些不必要的、难以阅读的lambda
s,做一些类似的事情:
def likes(names):
if len(names) > 3:
names = names[:2] + [f"{len(names)-2} others"]
elif len(names) == 0:
names = ["no-one"]
result = " and ".join(", ".join(names).rsplit(", ",1))
if len(names) == 1:
return result + " likes this"
else:
return result + " like this"
请发布错误的完整堆栈跟踪。提示:当names
为空时会发生什么?另外,如果执行names[3]
会发生什么?
>>> likes("")
Traceback (most recent call last):
File "<input>", line 1, in <module>
File "<input>", line 7, in likes
TypeError: 'str' object is not callable
{0:"no one likes this",
{0:(lambda names: "no one likes this"),
def likes(names):
if len(names) > 3:
names = names[:2] + [f"{len(names)-2} others"]
elif len(names) == 0:
names = ["no-one"]
result = " and ".join(", ".join(names).rsplit(", ",1))
if len(names) == 1:
return result + " likes this"
else:
return result + " like this"