如何将此文本文件转换为字典？（PYTHON）

我有一个.txt文件，内容如下：

Areca Palm
2018-11-03 18:21:26
Tropical/sub-Tropical plant
Leathery leaves, mid to dark green
Moist and well-draining soil
Semi-shade/full shade light requirements
Water only when top 2 inches of soil is dry
Intolerant to root rot
Propagate by cuttings in water

Canary Date Palm 
2018-11-05 10:12:15
Semi-shade, full sun
Dark green leathery leaves
Like lots of water,but soil cannot be water-logged
Like to be root bound in pot

我想将这些.txt文件转换为python上的dictionary，输出应该如下所示：

d = {'Areca Palm': ('2018-11-03 18:21:26', 'Tropical/sub-Tropical plant', 'Leathery leaves, mid to dark green', 'Moist and well-draining soil'..etc 'Canary Date Palm': ('2018-11-05 10:12:15', 'Semi-shade, full sun'...)

---

如何执行此操作？

以下代码显示了一种执行此操作的方法，使用非常简单的两状态机读取文件：

with open("data.in") as inFile:
    # Initialise dictionary and simple state machine.

    afterBlank = True
    myDict = {}

    # Process each line in turn.

    for line in inFile.readlines():
        line = line.strip()

        if afterBlank:
            # First non-blank after blank (or at file start) is key
            # (blanks after blanks are ignored).

            if line != "":
                key = line
                myDict[key] = []
                afterBlank = False
        else:
            # Subsequent non-blanks are additional lines for key
            # (blank after non-blank switches state).

            if line != "":
                myDict[key].append(line)
            else:
                afterBlank = True

# Dictionary holds lists, make into tuples if desired.

for key in myDict.keys():
    myDict[key] = tuple(myDict[key])

import pprint
pprint.pprint(myDict)

使用输入数据给出输出（使用

pprint

输出，使其比标准Python

print

更可读）：

---

通过编写函数，许多解析问题都大大简化了 处理文件并一次生成一个有意义的部分。 通常，这部分所需的逻辑非常简单。和 它保持简单，因为该函数与其他函数无关 关于更大问题的详细信息

然后，这一步骤简化了下游代码，重点是解构 一次一个有意义的部分。这一部分可以忽略更大的文件问题——也可以 保持简单

举例说明：

import sys

def get_paragraphs(path):
    par = []
    with open(path) as fh:         # The basic pattern tends to repeat:
        for line in fh:
            line = line.rstrip()
            if line:               # Store lines you want.
                par.append(line)
            elif par:              # Yield prior batch.
                yield par
                par = []
        if par:                    # Don't forget the last one.
            yield par

path = sys.argv[1]
d = {
    p[0] : tuple(p[1:])
    for p in get_paragraphs(path)
}

import sys

def get_paragraphs(path):
    par = []
    with open(path) as fh:         # The basic pattern tends to repeat:
        for line in fh:
            line = line.rstrip()
            if line:               # Store lines you want.
                par.append(line)
            elif par:              # Yield prior batch.
                yield par
                par = []
        if par:                    # Don't forget the last one.
            yield par

path = sys.argv[1]
d = {
    p[0] : tuple(p[1:])
    for p in get_paragraphs(path)
}