Python 为什么是价值；外部“U链接”；而不是从网站上刮下来的东西？

下面是我的代码，但是为什么

品牌

价值输出

外部链接

而不是我提取的项目列表

from bs4 import BeautifulSoup as soup
from urllib.request import urlopen as uReq


my_url = 'https://en.wikipedia.org/wiki/Harry_Potter'
uClient = uReq(my_url)
page_html = uClient.read()
uClient.close()

page_soup = soup(page_html,"html.parser")
headline = page_soup.findAll("span",{"class":"mw-headline"})

for item in headline:
    brand = item["id"] # Outputs "External_links"

---

在

for

循环中，您正在迭代页面中的每个标题，然后将标题值分配给变量

brand

。循环完成后，

brand

的值将成为最后一个标题（“外部链接”）

如果您修改代码以打印出每个标题的值，您将看到您正在获取所需的值

>>> for item in headline:
...    print(item["id"])
...
Plot
Early_years
Voldemort_returns
Supplementary_works
Harry_Potter_and_the_Cursed_Child
In-universe_books
Pottermore_website
Structure_and_genre
Themes
Origins
Publishing_history
Translations
Completion_of_the_series
Cover_art
Achievements
Cultural_impact
Commercial_success
Awards,_honours,_and_recognition
Reception
Literary_criticism
Social_impact
Controversies
Adaptations
Films
Spin-off_prequels
Games
Audiobooks
Stage_production
Attractions
The_Wizarding_World_of_Harry_Potter
The_Making_of_Harry_Potter
References
Further_reading
External_links

---

您的

品牌

变量需要是一个列表，例如，代码可能如下所示：

from bs4 import BeautifulSoup as soup
from urllib.request import urlopen as uReq
from pprint import pprint

my_url = 'https://en.wikipedia.org/wiki/Harry_Potter'
with uReq(my_url) as uClient:
    page_html = uClient.read()
    page_soup = soup(page_html, "xml")

brand = []
for item in page_soup.find_all('span', {'class': 'mw-headline'}):
    brand.append(item["id"])

pprint(brand)

印刷品：

['Plot',
 'Early_years',
 'Voldemort_returns',
 'Supplementary_works',
 'Harry_Potter_and_the_Cursed_Child',
 'In-universe_books',
 'Pottermore_website',
 'Structure_and_genre',
 'Themes',
 'Origins',
 'Publishing_history',
 'Translations',
 'Completion_of_the_series',
 'Cover_art',
 'Achievements',
 'Cultural_impact',
 'Commercial_success',
 'Awards,_honours,_and_recognition',
 'Reception',
 'Literary_criticism',
 'Social_impact',
 'Controversies',
 'Adaptations',
 'Films',
 'Spin-off_prequels',
 'Games',
 'Audiobooks',
 'Stage_production',
 'Attractions',
 'The_Wizarding_World_of_Harry_Potter',
 'The_Making_of_Harry_Potter',
 'References',
 'Further_reading',
 'External_links']

---

使用列表理解实现相同的目标：

import requests
from bs4 import BeautifulSoup
from pprint import pprint

url = 'https://en.wikipedia.org/wiki/Harry_Potter'

soup = BeautifulSoup(requests.get(url).text, "lxml")
items = [item.get('id') for item in soup.find_all('span',class_='mw-headline')]
pprint(items)

---

但我需要将其分配给一个变量，以便导出到csv，这可能吗？您可以创建一个列表，然后将每个标题添加到列表中，然后将列表的内容写入文件。