Python中的基本刽子手游戏

一周前我开始学习python，现在我正努力专注于非常基础的项目。我被困在“刽子手游戏”中

刽子手
这可能是这6个小项目中最难的一个 项目。这将类似于猜测数字，只是我们是 猜单词。用户需要猜测字母，给用户no 猜错字母的次数超过6次。这意味着你 必须有一个柜台

到目前为止，我已经编写了以下代码：

import random

name = input("Please enter your name to play Hangman! ")

print("Welcome "+name+" !. Lets play Hangman.")

wrong_attempt = int(input("How many incorrect attempts do you want ? "))

f = open('words.csv',"r")

secret_word = f.readline()
#print(secret_word)
guesses = ''
while wrong_attempt > 0 :
    c = 0
    letter = input("\nGuess a word : ")
    for char in secret_word :
        if char == letter :
            print(char,end = '')
        else :
            print('*',end = '')
            c += 1
            if c == len(secret_word) :
                wrong_attempt -= 1
                print("Bad Luck. You have ",wrong_attempt," attempts left.")
                print("The secret word is ",secret_word)

if wrong_attempt == 0 :
    print("You LOSE.")

我现在得到的输出：

Please enter your name to play Hangman! ss Welcome ss !. Lets play Hangman. How many incorrect attempts do you want ? 2

Guess a word : c c******** Guess a word : o
*o******* Guess a word : m
**m****** Guess a word : z
*********Bad Luck. You have  1  attempts left.

Guess a word : d
*********Bad Luck. You have  0  attempts left. You LOSE. The secret word is  computer

预期产出：

Please enter your name to play Hangman! ss Welcome ss !. Lets play Hangman. How many incorrect attempts do you want ? 2

Guess a word : c c******** Guess a word : o co******* Guess a word : m com****** Guess a word : z
*********Bad Luck. You have  1  attempts left.

Guess a word : d
*********Bad Luck. You have  0  attempts left. You LOSE. The secret word is  computer

---

此外，我是新的stackoverflow当谈到张贴问题。任何建议都将不胜感激。

我能看出的唯一区别是预期代码中的这一行：

猜一个词：c c**********猜一个词：o co*******猜一个词：m com*******猜一个词：z

而你的是：

猜一个词：c c*******猜一个词：o

*猜一个词：m **m*******猜一个词：z

因此，请尝试在结尾处\t而不是在此行中\n创建选项卡：

    letter = input("\nGuess a word : ")

---

我想这就是你的意思：

基本上，我所做的是创建一个列表并用astrik填充项目，然后在字符检查时，我弹出第n个astrik并用字母替换它

import random
import sys
name = input("Please enter your name to play Hangman! ")

print("Welcome "+name+" !. Lets play Hangman.")

wrong_attempt = int(input("How many incorrect attempts do you want ? "))

f = open('words.csv',"r")

secret_word = f.readline()
#print(secret_word)
guesses = ''
word = []
for i in secret_word.strip("\n"):
    word.append("*")
while wrong_attempt > 0 :
    word_str = ''.join([str(elem) for elem in word])

    #print(word_str)
    c = 0
    letter = input("\nGuess a word : ")
    for char in secret_word :
        if char == letter :
            word.pop(c)
            word.insert(c,char)
            c += 1
        else :
            c += 1
            if c == len(secret_word) :
                wrong_attempt -= 1
                print("Bad Luck. You have ",wrong_attempt," attempts left.")
                print("The secret word is ",secret_word)
    c=0

    word_str = ''.join([str(elem) for elem in word])
    print(word_str)
    if word_str == secret_word.strip("\n"):
        print("Yeee, you won")
        sys.exit()
if wrong_attempt == 0 :
    print("You LOSE.")

---

在您的输出中，您不想要什么不同？在您的代码中，您没有考虑到迄今为止正确猜测的字母，只有在本次循环中猜测的字母。我建议您创建一个字符串，用

******

（长度正确）初始化，并在猜测过程中实现。这也会让你知道玩家是否赢得了比赛。我还建议您在

trunt\u left

中将变量重命名为`error\u trunt`，它的名称是误读的。如果您阅读了代码，那么您会看到每一行都在单独的一行上。代码中的问题是，每次猜测都只能看到该尝试中正确的字母。