Python 如何根据属性问题区分动物之间的差异

我正在创建一个程序，一个人工智能。事实上，它通过一系列问题来学习动物之间的差异，这些问题将决定动物在头脑中拥有哪些属性。所以我想要的是一种通过选择属性问题来存储动物的方法，例如：

dog : does it have a wet nose?
      does it have whiskers?

dog : does it have a wet nose?
      does it have whiskers?
cat : does it purr?
      does it have whiskers?

   for each question:
     for each word in question :
       if word in attributes:
         attributesFound.append(word)
   animal=set(dic[attributesFound[0]])
   for each attribute in attributesFound:
   animal=animal.intersection(dict[attribute ])

所有这些回答“是”的问题都是狗的属性……有什么想法吗？还要记住，有些动物具有相同的属性，例如：

dog : does it have a wet nose?
      does it have whiskers?

dog : does it have a wet nose?
      does it have whiskers?
cat : does it purr?
      does it have whiskers?

   for each question:
     for each word in question :
       if word in attributes:
         attributesFound.append(word)
   animal=set(dic[attributesFound[0]])
   for each attribute in attributesFound:
   animal=animal.intersection(dict[attribute ])

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因此，我希望程序能够提出多个问题，并确定哪种动物是哪种动物。

我认为您可以使用a来完成这项任务，您可以使用它根据动物的属性对动物进行分类，也可能有助于查看，它将帮助您确定进行分类的最佳属性。

您可以做的最简单的事情是使用字典，它将保持属性与具有该属性的动物列表之间的关系，例如：

attributes=[bite,scratch,purr,whiskers,...]
dic={
whiskers:[cat,dog]
purr:[cat]
scratch:[cat]
bite:[cat,dog,rat]}
dose it scratch

根据您的问题格式，例如：

dog : does it have a wet nose?
      does it have whiskers?

dog : does it have a wet nose?
      does it have whiskers?
cat : does it purr?
      does it have whiskers?

   for each question:
     for each word in question :
       if word in attributes:
         attributesFound.append(word)
   animal=set(dic[attributesFound[0]])
   for each attribute in attributesFound:
   animal=animal.intersection(dict[attribute ])

说我们有这个案子

      does it purr?
      does it have whiskers?

找到的属性将是[purr，whiskers]，animal将是[cat，dog]，然后我们进入for each属性循环

 for each attribute in [cat,dog] :
   animal=set(animal.intersection(dict[attribute ]))//in the first iteration animal would still be [cat,dog].

//然而，在第二次迭代中，集合（[cat，dog]交集（[cat]）只会留下一个集合，其中只有一个元素是cat