Python 该函数返回none

Python 该函数返回none,python,python-3.x,Python,Python 3.x,它应该给出整数。这是一个关于hackerrank-Equal堆栈的问题 def equalStacks(h1, h2, h3): # # Write your code here. # stackSum = sumOfStack(h1, h2, h3) (stackSum1, stackSum2, stackSum3) = stackSum if stackSum1 == stackSum2 and stackSum1 == stackSum3

它应该给出整数。这是一个关于hackerrank-Equal堆栈的问题

def equalStacks(h1, h2, h3):
    #
    # Write your code here.
    #
    stackSum = sumOfStack(h1, h2, h3)

    (stackSum1, stackSum2, stackSum3) = stackSum

    if stackSum1 == stackSum2 and stackSum1 == stackSum3:
        return stackSum1

    elif stackSum1 <= stackSum2:
        if stackSum2 > stackSum3:
            equalStacks(h1, h2[1:], h3)
        else:
            equalStacks(h1, h2, h3[1:])

    elif stackSum2 <= stackSum3:
        if stackSum3 > stackSum1:
            equalStacks(h1, h2, h3[1:])
        else:
            equalStacks(h1[1:], h2, h3)
    elif stackSum2 <= stackSum1:
        if stackSum1 > stackSum3:
            equalStacks(h1[1:], h2, h3)
        else:
            equalStacks(h1, h2, h3[1:])
    else:
        return -1



def sumOfStack(h1, h2, h3):
        sumN1 = sum(h1)
        sumN2 = sum(h2)
        sumN3 = sum(h3)
        return [sumN1, sumN2, sumN3]

第一个if语句应该返回整数,而不是返回None。

不是在每个执行路径中都返回值


在每次调用
equalStacks
之前添加
return

可能的重复:请澄清您的测试用例
5 3 4,
3 2 1 1 1,
4 3 2,
1 1 4 1