Python peewee:如何基于另一个表中跨行的值筛选表中的数据

Python peewee:如何基于另一个表中跨行的值筛选表中的数据,python,sql,peewee,Python,Sql,Peewee,考虑以下支持peewee的python代码,如何基于另一个表中跨行的值筛选表中的数据 e、 g。 如果我想在note表中获得一个note,该表包含java,lambda,generics标签,位于customtags #!/usr/bin/env python3 import peewee import datetime db = peewee.SqliteDatabase('test.db') class Note(peewee.Model): id = peewee.AutoF

考虑以下支持peewee的python代码,如何基于另一个表中跨行的值筛选表中的数据

e、 g。 如果我想在note表中获得一个note,该表包含
java
lambda
generics
标签,位于
customtags

#!/usr/bin/env python3

import peewee
import datetime

db = peewee.SqliteDatabase('test.db')

class Note(peewee.Model):
    id = peewee.AutoField()
    name = peewee.CharField()
    text = peewee.CharField()
    created = peewee.DateField(default=datetime.date.today)

    class Meta:

        database = db
        db_table = 'notes'

class CustomTag(peewee.Model):
    id = peewee.AutoField()
    note = peewee.ForeignKeyField(Note, backref='notes')
    tag = peewee.CharField()

    class Meta:

        database = db
        db_table = 'customtags'
        indexes = ((("note_id", "tag"), True),)

Note.drop_table()
CustomTag.drop_table()
Note.create_table()
CustomTag.create_table()

note1 = Note.create(name="note1",text='Java 8 lambda with generics')
note1.save()
CustomTag.insert(note=note1, tag='java').on_conflict_ignore(True)
CustomTag.insert(note=note1, tag='lambda').on_conflict_ignore(True)
CustomTag.insert(note=note1, tag='generics').on_conflict_ignore(True)

note2 = Note.create(name="note2",text='Core Java concepts',
        created=datetime.date(2018, 10, 20))
note2.save()
CustomTag.insert(note=note2, tag='java').on_conflict_ignore(True)

note3 = Note.create(name="note3",text='Java collection framework',
        created=datetime.date(2018, 10, 22))
note3.save()
CustomTag.insert(note=note3, tag='java').on_conflict_ignore(True)

note4 = Note.create(name="note4",text='Java NIO packageJava nio package')
note4.save()
CustomTag.insert(note=note4, tag='java').on_conflict_ignore(True)

notes = Note.select().join(CustomTag, peewee.JOIN.LEFT_OUTER,on=(Note.id == CustomTag.note_id)).order_by(Note.name)

for note in notes:
    print('{} with text {} on {}'.format(note.name, note.text, note.created))
我真的不知道如何修改我的代码来获取上面提到的数据,我知道问题出在下面的代码中

notes = Note.select().join(CustomTag, peewee.JOIN.LEFT_OUTER,on=(Note.id == CustomTag.note_id)).order_by(Note.name)

e、 如果我想在note表中得到一个note,在customtags中包含所有java、lambda、generics标记

insert语句中似乎缺少
execute()
。它应该在每一行中更正

CustomTag.insert(note=note1, tag='java').on_conflict_ignore(True).execute()
我在这里加入了coleifer答案的改进版本,结果还包括标签列表

from peewee import fn 

filter_tags = ['java', 'lambda', 'generics']
notes = (Note
         .select(Note, fn.GROUP_CONCAT(CustomTag.tag,',').alias('tags'))
         .join(CustomTag)
         .where(CustomTag.tag.in_(filter_tags))
         .group_by(Note)
         .having(fn.COUNT(CustomTag.id) >= len(filter_tags)))

for note in notes:
    print(f'name : {note.name} text: {note.text} tags: {note.tags} created : {note.created}')
from peewee import fn 

filter_tags = ['java', 'lambda', 'generics']
notes = (Note
         .select(Note, fn.GROUP_CONCAT(CustomTag.tag,',').alias('tags'))
         .join(CustomTag)
         .where(CustomTag.tag.in_(filter_tags))
         .group_by(Note)
         .having(fn.COUNT(CustomTag.id) >= len(filter_tags)))

for note in notes:
    print(f'name : {note.name} text: {note.text} tags: {note.tags} created : {note.created}')